jq:将对象数组转换为对象 [英] jq: translate array of objects to object
问题描述
我收到curl的回复,格式如下:
I have a response from curl in a format like this:
[
{
"list": [
{
"value": 1,
"id": 12
},
{
"value": 15,
"id": 13
},
{
"value": -4,
"id": 14
}
]
},
...
]
给出这样的ID之间的映射:
Given a mapping between ids like this:
{
"12": "newId1",
"13": "newId2",
"14": "newId3"
}
我要这样做:
[
{
"list": {
"newId1": 1,
"newId2": 15,
"newId3": -4,
}
},
...
]
这样我就得到了从ID到值的映射(并希望重新映射ID).
Such that I get a mapping from ids to values (and along the way I'd like to remap the ids).
我已经为此工作了一段时间,每次我都陷入僵局.
I've been working at this for a while and every time I get a deadend.
注意:如有必要,我可以使用Shell或类似工具执行循环.
Note: I can use Shell or the like to preform loops if necessary.
edit:这是我到目前为止开发的一个版本:
edit: Here's one version what I've developed so far:
jq '[].list.id = ($mapping.[] | select(.id == key)) | del(.id)' -M --argjson "mapping" "$mapping"
我认为这不是最好的版本,但是我正在寻找是否可以找到更接近我所需的旧版本.
I don't think it's the best one, but I'm looking to see if I can find an old version that was closer to what I need.
推荐答案
[当以下描述描述(a)如下所示的映射,以及(b)输入数据具有表格:
[ The following response was in answer to the question when it described (a) the mapping as shown below, and (b) the input data as having the form:
[
{
"list": [
{
"value": 1,
"id1": 12
},
{
"value": 15,
"id2": 13
},
{
"value": -4,
"id3": 14
}
]
}
]
编辑结束]
在下面,我将假定可以通过以下函数使用该映射,但这是一个无关紧要的假设:
In the following I'll assume that the mapping is available via the following function, but that is an inessential assumption:
def mapping: {
"id1": "newId1",
"id2": "newId2",
"id3": "newId3"
} ;
然后,以下jq过滤器将产生所需的输出:
The following jq filter will then produce the desired output:
map( .list
|= (map( to_entries[]
| (mapping[.key]) as $mapped
| select($mapped)
| {($mapped|tostring): .value} )
| add) )
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