如何转换为IEnumerable＆LT;任务＆LT; T＆GT;＆GT;到的IObservable＆LT; T＆GT; [英] How to convert an IEnumerable<Task<T>> to IObservable<T>

问题描述

有一个内置的方式来转换一个IEnumerable＆LT;任务＆LT; T＆GT;＆GT;到的IObservable＆LT; T＆取代。顺序并不重要，只是我得到的东西，虽然preferably，因为它们可以完成。

Is there a built in way to convert an IEnumerable<Task<T>> to an IObservable<T>. Order doesn't matter, just that I get things, though preferably as they're completed.

如果它还不存在，可能是什么来完成它的好办法？

If it doesn't exist yet, what might be a good way to accomplish it?

推荐答案

我相信这将工作

tasks.Select(t => Observable.FromAsync(() => t))
     .Merge();

每个任务会送其结果的任何顺序完成可观察序列。您可以订阅的顺序和做任何你想要的结果的方式。

Each task will send its results to the observable sequence in whatever order they complete. You can subscribe to the sequence and do whatever you want with the results that way.

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