从控制器返回Json数据以查看ASP.NET MVC [英] Returning Json Data From Controller to View ASP.NET MVC

问题描述

我正按照标题所说的那样，在验证后从Controller向视图返回Json消息.

I am trying as the title says to return a Json message from the Controller to the View after it validates.

我已经创建了一个断点，并且我知道代码可以在Controller端运行，并且我的JavaScript现在成功调用了ActionResult.如何在视图"中显示该消息?

I have made a breakpoint, and I know that the code works from Controller side, and that my JavaScript calls with success the ActionResult now. How do I display that message in the View?

有两个按钮，戳入和戳出.如果用户加盖两次，则应该会收到一条消息，与加盖戳相同.除了一些消息和字符串更改之外，我有两个相同的ActionResult.

There are two buttons, stamp in and stamp out. If the user stamps in twice, it should get a message, same with stamp out. I have two ActionResults who are indentical except some message and string changes.

控制器:

[HttpPost]
    public ActionResult CreateStamp(Stamping stampingmodel)
    {
        var validateMsg = "";
        stampingmodel.Timestamp = DateTime.Now;
        stampingmodel.StampingType = "in";

        if (stampingmodel.User == null || ModelState.IsValid)
        {
            var idValidated = db.Users.Find(model.UserId);

            if (idValidated != null)
            {
                var stamp =
                    db.Stampings.Where(s => s.UserId == stampingmodel.UserId)
                        .OrderByDescending(s => s.Timestamp)
                        .FirstOrDefault();

                if (stamp.StampingType == stampingmodel.StampingType)
                {
                    if (stampingmodel.StampingType == "in")
                    {
                        validateMsg = "Stamped Twice In A Row!";
                    }
                }

                else
                {
                    if (stampingmodel.StampingType == "in")
                    {
                        validateMsg = "Stamped In, Welcome.";
                    }
                }
            }

            db.Stampings.Add(stampingmodel);
            db.SaveChanges();
        }

        return Json(new {Message = validateMsg });

JavaScript:

JavaScript:

$(document).ready(function () {

$("#stampInBtn").click(function () {

    var userId = $("#userId").val();

    $.ajax({
        url: "ComeAndGo/CreateStamp",
        type: "POST",
        dataType: "json",
        data: {
            userId: userId,
        }
    });

});

查看:

    <input type="text" id="idUser" class="form-control" />
    <br />
    <input type="submit" value="IN" id="stampInBtn" />

我当然在View中有更多代码； div，标题，正文，标题和脚本.但这可能有点无关紧要.

I have more code inside the View of course; divs, head, body, title and scripts. But it's perhaps a little irrelevant.

我该怎么做才能成功显示这些消息?

What should I do to successfully show those messages?

致谢.

推荐答案

向ajax调用添加成功函数

Add a success function to the ajax call

$.ajax({
  url: "ComeAndGo/CreateStamp",
  type: "POST",
  dataType: "json",
  data: { userId: userId },
  success: function(data) {
    // data contains the value returned by the server
    console.log(data);
  }     
});

因此，如果控制器返回

return Json("This is a message");

data的值将为这是一条消息" .请注意，返回值可以是复杂类型或局部视图

the value of data will be "This is a message". Note the return value can be a complex type or a partial view

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