PHP并将MySQL行封装到JSON数组中 [英] PHP and encapsulating MySQL rows into a JSON array

问题描述

我正在玩一个留言簿/聊天室的主意，并设置了一个包含三列的MySQL表:

I'm playing with a guestbook/chatroom idea and have a MySQL table setup with three columns:

1-id-主键自动递增

1 - id - Primary Key auto increment

2-名称-字符串

3-评论-字符串

我对PHP的经验很少，但这是我为此操作汇总的内容:

I have very little experience with PHP but this is what I've put together for this operation:

$result = mysql_query("SELECT * FROM guestbook");
$i = 0;
while($row = mysql_fetch_array($result))
  {
      //add the row to the $chat array at specific index of $i
      $chat[$i] = $row;
      $i += 1;
  }

$encode = json_encode($chat);
echo "$encode";

但是，此输出看起来很糟糕:

However, output from this looks pretty awful:

[{"0":"1","id":"1","1":"Justin ","name":"Justin ","2":"Comment 1","comment":"Comment 1"},
{"0":"2","id":"2","1":"Justin ","name":"Justin ","2":"Another comment","comment":"Another comment"},
{"0":"3","id":"3","1":"Justin ","name":"Justin ","2":"Look at this comment!","comment":"Look at this comment!"},
{"0":"4","id":"4","1":"Justin ","name":"Justin ","2":"Ok I'm done talking","comment":"Ok I'm done talking"}]

我希望获得三个字段:id，name和comment，但看起来好像翻了一番.有人可以帮忙吗?

I was hoping to get three fields: id, name, and comment, but it looks like things doubled. Can anyone help?

谢谢！

推荐答案

释义Marc，只需替换此行:

To paraphrase Marc, Just replace this line:

while($row = mysql_fetch_array($result))

与此:

while($row = mysql_fetch_array($result, MYSQL_ASSOC))

获取更清晰的JSON.默认情况下，mysql_fetch_array()将同时返回整数索引和关联索引，您只需要关联索引.

To get cleaner JSON. By default mysql_fetch_array() will return both an integer index and an associative index, you only want the associative index.

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