使用Sql Server 2016的OPENJSON函数从Json文档中的多个数组元素中选择结果 [英] Select results from multiple array elements in Json document with Sql Server 2016's OPENJSON function

问题描述

在Sql Server 2016中是否可以将多个数组元素中的json文档的一部分合并为一个结果?

Is it possible to combine parts of a json document from multiple array elements into a single result in Sql Server 2016?

给出此json:

{
  "fruit": {
    "types": [
      {
        "possible": [ "Apples", "Bananas", "Pears" ],
        "category": "Basic"
      },
      {
        "possible": [ "Oranges", "Grapefruit", "Lemons", "Limes" ],
        "category": "Citrus"
      },
      {
        "possible": [ "Blueberries", "Strawberries", "Cherries" ],
        "category": "Berries"
      }
    ]
  }
}

我想查看可能元素中所有值的单个结果:

I'd like to see a single result of all the values from the possible element:

results
-----
Apples
Bananas
Pears
Oranges
Grapefruit
Lemons
Limes
Blueberries
Strawberries
Cherries

我已经很接近了:

SELECT * FROM OPENJSON(JSON_QUERY(@json, '$.fruit.types[0].possible'))
UNION
SELECT * FROM OPENJSON(JSON_QUERY(@json, '$.fruit.types[1].possible'))
UNION
SELECT * FROM OPENJSON(JSON_QUERY(@json, '$.fruit.types[2].possible'))

但这依赖于将查询绑定到数组中元素的数量. 有没有一种方法可以不必单独指定每个数组元素?这样的东西(都不是有效的表达式):

But this relies on tying the query to the number of elements in the array. Is there a way to do it without having to specify each array element individually? Something like this (neither of these are valid expressions):

SELECT * FROM OPENJSON(JSON_QUERY(@json, '$.fruit.types[].possible'))

或

SELECT * FROM OPENJSON(JSON_QUERY(@json, '$.fruit.types.possible'))

这是我应该进行交叉申请的地方吗?

Is this where I should be doing a CROSS APPLY?

推荐答案

这是我应该进行交叉申请的地方吗?

Is this where I should be doing a CROSS APPLY?

是的

declare @json nvarchar(max)='
{
  "fruit": {
    "types": [
      {
        "possible": [ "Apples", "Bananas", "Pears" ],
        "category": "Basic"
      },
      {
        "possible": [ "Oranges", "Grapefruit", "Lemons", "Limes" ],
        "category": "Citrus"
      },
      {
        "possible": [ "Blueberries", "Strawberries", "Cherries" ],
        "category": "Berries"
      }
    ]
  }
}
'

select v.value
from openjson(@json, '$.fruit.types') t
cross apply openjson(t.value,'$.possible') v

输出

value
---------
Apples
Bananas
Pears
Oranges
Grapefruit
Lemons
Limes
Blueberries
Strawberries
Cherries

(10 row(s) affected)

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