如何将Json转换为Xml [英] How to Json To Xml

问题描述

我是Json的新手，我有一个简单的问题.

I am new for Json and I have a simple problem.

我正在尝试使用C#将json文件转换为xml文件.但这会引发异常.

I am trying to convert json file to xml file with c#. But it throw an exception.

代码为;

  private void TakeXML()
    {
        string json = ReadText();

        XmlDocument doc = (XmlDocument)Newtonsoft.Json.JsonConvert.DeserializeXmlNode(json);

        XmlTextWriter writer = new XmlTextWriter("json.xml", null);
        writer.Formatting = Formatting.Indented;
        doc.Save(writer);
    }

ReadText函数是;

The ReadText function is;

 private string ReadText()
    {
        FileStream fs = new FileStream(@"C:\Users\Sinan\Desktop\bina.json", FileMode.Open, FileAccess.Read);
        StreamReader sr = new StreamReader(fs);
        string json;
        try
        {
            json = sr.ReadToEnd();
            return json;

        }
        catch (Exception)
        {
            return null;
        }
        finally
        {

            sr.Close();
            fs.Dispose();
        }
    }

对于XmlDocument doc = (XmlDocument)Newtonsoft.Json.JsonConvert.DeserializeXmlNode(json);行，它表示；

"JSON根对象具有多个属性.该根对象必须具有单个属性才能创建有效的XML文档.请考虑指定DeserializeRootElementName."

"JSON root object has multiple properties. The root object must have a single property in order to create a valid XML document. Consider specifing a DeserializeRootElementName."

我正在寻找解决此问题的方法，但ı尚未找到.如果您在这方面帮助我，我会很高兴的.谢谢.

I am searching to solve this problem but ı haven't found it. İf you help me in this regard, I will be glad. Thank you.

推荐答案

在方法DeserializeXmlNode中，在第二个参数中指定根节点名称，如以下代码所示:

In method DeserializeXmlNode specify the root node name in second parameter as shown in below code:

XmlDocument doc =
  (XmlDocument)
     Newtonsoft.Json.JsonConvert.DeserializeXmlNode(json, "rootNodeName");
                                                   // second parameter

尽管可以给出json字符串，但给出确切答案很容易.

Although if you can give json string then it would be easy to give exact answer.

参考链接:将JSON转换为XML

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