用resttemplate解析json [英] json parsing with resttemplate

问题描述

我有一个如下的json响应

I have a json response as below

{
    "@odata.context": "some context value here",
    "value": [{
        "@odata.id": "odata id value1",
        "@odata.etag": "W/\"CQEet/1EgOuA\"",
        "Id": "id1",
        "Subject": "subject1"
    }, {
        "@odata.id": "odata id value2",
        "@odata.etag": "W/\"CyEet/1EgOEk1t/\"",
        "Id": "id2",
        "Subject": "subject2"
    }]
}

如何使用Spring RestTemplate创建一个bean类(MyMessage)来解析值"?

How do I create a bean class(MyMessage) to parse the "value" using spring resttemplate?

RestTemplate rest = new RestTemplate();
ResponseEntity<MyMessage> response = rest.exchange(url, HttpMethod.GET, entity, MyMessage.class);

有人可以帮忙吗?

推荐答案

使用@JsonProperty注释bean属性，以设置该属性的JSON字段名称(如果不同).

Annotate bean properties with @JsonProperty to set JSON field name for the property if it is different.

请参阅:

JsonProperty注释和何时@使用的JsonProperty属性及其用途是什么?

示例(为简单起见，bean属性是公共的):

Example (bean properties are public for example simplicity):

MyMessage类:

MyMessage class:

public class MyMessage {

    @JsonProperty("@odata.context")
    public String context;

    @JsonProperty("value")
    public Value[] values;
}

值类别:

// PascalCaseStrategy is to resolve Id and Subject properties
@JsonNaming(PascalCaseStrategy.class)
public class Value {

    @JsonProperty("@odata.id")
    public String odataId;

    @JsonProperty("@odata.etag")
    public String odataEtag;

    public String id;
    public String subject;
}

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