从数组值创建JavaScript对象 [英] Creating javascript object from array values

问题描述

我正在尝试创建一个javascript对象，以便可以将其转换为json字符串，以便通过php更新mysql表.我是Java语言中的对象和json的新手，所以我在网络上关注了一些教程，但似乎仍然无法使它起作用:

I am attempting to create a javascript object so that I can tranfsorm it into a json string in order to update a mysql table via php. I'm new to objects and json in javascript and so I have followed a couple of tutorials on the web but still can't seem to be getting this to work:

var idArray =      [ 1, 2, 3];
var slideNo =      [ 1, 2, 3];
var isPublished =  [ 0, 1, 0];
var floaText =     [ 1, 0 , 1];

var myObject = [];

for(var i = 0; i < idArray.length; i++) {
    myObject[i] = {
        slideId : idArray[i],
        slideNo : slideNo [i],
        isPublished : isPublished [i],
        floatText : floaText [i]
    };
}

alert(myObject[0].slideId);

我似乎无法获得上述代码.我还尝试添加如下形式的报价单:

I can't seem to get the above code work. I also tried to add quoation makrs like this:

myObject[i] = {
    slideId : "\"" + idArray[i] + "\"",
    slideNo : "\"" + slideNo[i] + "\"",
    isPublish : "\"" + isPublished[i] + "\"",
    floatText : "\"" + floaText[i]
};

但这似乎也不起作用.我在做什么错了?

But that doesn't seem to work either. What am I doing wrong?

推荐答案

看起来像您最近的编辑解决了以下问题之一:您需要在数组周围使用[]，而不是{}.

Looks like your recent edit fixed one of the issues: you need [] around your arrays, not {}.

接下来，您需要更改数组变量名称以匹配您在for循环中使用的名称.

Next, you need to change your array variable names to match what you're using in your for loop.

最后，myObject可能应该是数组，而不是对象，因此将其{}更改为[].

Finally, myObject should probably be an array, not an object, so change its {} to [].

这是您代码的更新版本:

Here's an updated version of your code:

var idArray =         [ 1, 2, 3];
var slideArray =      [ 1, 2, 3];
var publishArray =    [ 0, 1, 0];
var floatArray =      [ 1, 0 , 1];

var myObject = [];

for(var i = 0; i < idArray.length; i++) {
    myObject[i] = {
        slideId : idArray[i],
        slideNo : slideArray[i],
        isPublished : publishArray[i],
        floatText : floatArray[i]
    };
}

alert(myObject[0].slideId);

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