将Rest API JSON响应转换为C#对象 [英] Convert Rest API JSON Response into C# object

问题描述

我有一个代码REST API响应，它是json，并解析为JObject并从中提取一个值.但是我在解析到JObject时遇到了错误.

I have a code REST API response which is json, and parsing to JObject and pulling a value from it. But i am getting the error when parsing to JObject.

错误:解析值时遇到意外字符:S. Path"，第0行，位置0."

Error: "Unexpected character encountered while parsing value: S. Path '', line 0, position 0."

还有其他方法可以将Json字符串转换为C#对象.

Is there any other way to convert Json string to C# object.

我有以下代码: 使用Newtonsoft.Json;

I have the following code: using Newtonsoft.Json;

    using (HttpResponseMessage message = httpclient.GetAsync(folderIdURL).Result)
    {
        if(message.IsSuccessStatusCode)
        {
            var dataobjects = message.Content.ReadAsStringAsync();
            //dataobjects = "{"id":"https://gbc-dev5.cloud.wc.com/DctmRest/repositories/dmgbsap_crt/","title":"DQL query results","author":[{"name":"EMC Documentum"}],"updated":"2019-05-02T15:19:52.508+00:00","page":1,"items-per-page":100,"links":[{"rel":"self","href":"https://gbc-dev5.cloud.wc.com/DctmRest/repositories/dmgbsap_crt/?dql=SELECT%20r_object_id%2cobject_name%20FROM%20dm_sysobject%20WHERE%20FOLDER%20(%27%2fgbc%2fUS%2fOSA-ATTACHMENT%2f2019%27)"}],"entries":[{"id":"https://gbc-dev5.cloud.wc.com/DctmRest/repositories/dmgbsap_crt/?dql=SELECT%20r_object_id%2cobject_name%20FROM%20dm_sysobject%20WHERE%20FOLDER%20(%27%2fgbc%2fUS%2fOSA-ATTACHMENT%2f2019%27)&index=0","title":"0b0111738011c114","updated":"2019-05-02T15:19:52.508+00:00","published":"2019-05-02T15:19:52.508+00:00","links":[{"rel":"edit","href":"https://gbc-dev5.cloud.wc.com/DctmRest/repositories/dmgbsap_crt/objects/0b0111738011c114"}],"content":{"json-root":"query-result","definition":"https://gbc-dev5.cloud.wc.com/DctmRest/repositori                      es/dmgbsap_crt/types/dm_sysobject","properties":{"r_object_id":"0b0111738011c114","object_name":"04"},"links":[{"rel":"self","href":"https://gbc-dev5.cloud.wc.com/DctmRest/repositories/dmgbsap_crt/objects/0b0111738011c114"}]}},{"id":"https://gbc-dev5.cloud.wc.com/DctmRest/repositories/dmgbsap_crt/?dql=SELECT%20r_object_id%2cobject_name%20FROM%20dm_sysobject%20WHERE%20FOLDER%20(%27%2fgbc%2fUS%2fOSA-ATTACHMENT%2f2019%27)&index=1","title":"0b0111738011c115","updated":"2019-05-02T15:19:52.509+00:00","published":"2019-05-02T15:19:52.509+00:00","links":[{"rel":"edit","href":"https://gbc-dev5.cloud.wc.com/DctmRest/repositories/dmgbsap_crt/objects/0b0111738011c115"}],"content":{"json-root":"query-result","definition":"https://gbc-dev5.cloud.wc.com/DctmRest/repositories/dmgbsap_crt/types/dm_sysobject","properties":{"r_object_id":"0b0111738011c115","object_name":"05"},"links":[{"rel":"self","href":"https://gbc-dev5.cloud.wc.com/DctmRest/repositories/dmgbsap_crt/objects/0b0111738011c115"}]}}]}"

            JObject responseObj = JObject.Parse(dataobjects.ToString());
            String id = (String)responseObj["entries" -->"content"-->"properties"-->"object_name"];
        }                                      

    }

}

我期望(String)responseObject ["enteries"] ["content"] ["properties"] ["object_name"]中的值

I am expecting the value from (String)responseObject["enteries"]["content"][" properties"]["object_name"]

推荐答案

JObjects很痛苦.您可以获取JSON响应的示例，并将其粘贴到json2csharp.com之类的转换器中.它将为您生成一个类，您可以像这样使用它:

JObjects are a pain. You could get a sample of the JSON response and paste it into a converter like json2csharp.com. It will generate a class for you which you can then use like so:

生成的类:

public class MyClass
{
    public string SomeProperty { get; set; }
    public string AnotherProperty { get; set; }
}

用法:

if (message.IsSuccessStatusCode)
{
     var deserializedObject = JsonConvert.DeserializeObject<MyClass>(response.Content.ReadAsStringAsync().Result);
     Console.WriteLine(deserializedObject.SomeProperty);
}

这篇关于将Rest API JSON响应转换为C#对象的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！