如何在Python中获得特定级别的JSON? [英] How can I get certain levels of JSON in Python?

问题描述

如果我的JSON数据如下所示:

If my JSON data looks like this:

{
    "name": "root",
    "children": [
        {
            "name": "a",
            "children": [
                {
                    "name": "b",
                    "children": [
                        {
                            "name": "c",
                            "size": "1"
                        },
                        {
                            "name": "d",
                            "size": "2"
                        }
                    ]
                },
                {
                    "name": "e",
                    "size": 3
                }
            ]
        },
        {
            "name": "f",
            "children": [
                {
                    "name": "g",
                    "children": [
                        {
                            "name": "h",
                            "size": "1"
                        },
                        {
                            "name": "i",
                            "size": "2"
                        }
                    ]
                },
                {
                    "name": "j",
                    "size": 5
                }
            ]
        }
    ]
}

如何在Python中返回两个相邻的级别?

How can I return two adjacent levels in Python?

例如返回:
a-b，e
f-g，j

For example return:
a - b,e
f - g,j

数据可能会变得非常大，因此我必须将其切成小块.

The data could become very large, therefore I have to slice it into smaller pieces.

感谢您的帮助.

推荐答案

您需要构建一棵dict s的树，其值作为叶子:

You need to build a tree of dicts, with values as the leaves:

{'a': {'b': {'c': '1', 'd': '2'}, 'e': '3'}, 'f': {'g': {'h': '1', 'i': '2'}, 'j': '5'}}

这可以分解为三个独立的动作:

This can be decomposed into three separate actions:

1. 获取节点的"name"作为键
2. 如果节点具有"children"，请将其转换为dict
3. 如果节点具有"size"，则将其转换为单个值

1. get the "name" of a node for use as a key
2. if the node has "children", transform them to a dict
3. if the node has a "size", transform that to the single value

除非您的数据是深层嵌套的，否则递归是一种简单的方法:

Unless your data is deeply nested, recursion is a straightforward approach:

def compress(node: dict) -> dict:
    name = node['name']  # get the name
    try:
        children = node['children']  # get the children...
    except KeyError:
        return {name: node['size']}  # or return name and value
    else:
        data = {}
        for child in children:       # collect and compress all children
            data.update(compress(child))
        return {name: data}

这将压缩整个层次结构，包括"root"节点:

This compresses the entire hierarchy, including the "root" node:

 >>> compress(data)
 {'root': {'a': {'b': {'c': '1', 'd': '2'}, 'e': 3},
           'f': {'g': {'h': '1', 'i': '2'}, 'j': 5}}}

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