将JSON反序列化为带有Childs的C#对象 [英] Deserialize JSON to C# Objects with Childs

问题描述

我有一个JSON字符串，我需要一些帮助来反序列化它. 目前，我的结果始终为空.

I have a JSON string and I need some help to deserialize it. At the moment my result is always null.

var results = JsonConvert.DeserializeObject<Root>(json);
// result == null

我的JSON:

{"First":{"FirstData1":{"date":"2018-01-01","hint":""},
"FirstData2":{"date":"2018-01-06","hint":""}},
"Second":{"SecondData1":{"date":"2018-01-01","hint":""},
"SecondData2":{"date":"2018-01-06","hint":""}}}....

只有在最后一个节点上才有实际的属性命名...

Only on the last Node there is actual property naming...

MyObjects

MyObjects

public class Root
{
    public IEnumerable<TempModelRoot> Value{ get; set; }
}

public class TempModelRoot
{
    [JsonProperty("Key")]
    public string Key { get; set; }

    [JsonProperty("Value")]
    public List<TempModelChild> Value { get; set; }
}

public class TempModelChild
{
    [JsonProperty("Key")]
    public string Key { get; set; }

    [JsonProperty("Value")]
    public TempModelInfo Value { get; set; }
}


public class TempModelInfo
{
    [JsonProperty("date")]
    public string date { get; set; }

    [JsonProperty("hint")]
    public string hint { get; set; }
}

推荐答案

您极有可能在尝试反序列化的模型与基于json本身的实际预期模型之间不匹配.

Most likely you are having a mismatch between the model you are trying to deserialize to, and the actual expected model based of the json itself.

一种简单的解决方法是使用诸如快速类型模型的工具生成器 ^{(未附加功能)}，它使您可以基于提供的json文件生成C#模型.

A easy way to resolve this is by using a tool such as Quick Types Model Generator^{(unafiliated)} which allows you to generate C# models based upon a provided json file.

生成后，您可以将模型与生成的模型进行比较和/或替换. 找出并解决模型问题.

After generation you can compare and/or replace your models with the generated models. To spot and resolve the issue with your model.

这篇关于将JSON反序列化为带有Childs的C#对象的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！