转换将对象字符串转换为JSON或Object [英] convert "converted" object string to JSON or Object

问题描述

自从我升级了我的prototypeJS框架以来，我一直在关注以下问题.

i've following problem and since i upgraded my prototypeJS framework.

JSON解析不再能够将该字符串转换为对象.

the JSON parse is not able anymore to convert this string to an object.

"{empty: false, ip: true}"

以前在1.6版中是有可能的，现在它必须是一个经过验证"的JSON字符串，例如

previously in version 1.6 it was possible and now it needs to be a "validated" JSON string like

'{"empty": false, "ip": true}'

但是如何将第一个示例转换回对象?

But how can i convert the 1st example back to an object?

推荐答案

JSON需要所有键都加引号，因此:

JSON needs all keys to be quoted, so this:

"{empty: false, ip: true}"

不是有效的JSON.您需要对其进行预处理，以便能够解析此JSON.

is not a valid JSON. You need to preprocess it in order to be able to parse this JSON.

function preprocessJSON(str) {

    return str.replace(/("(\\.|[^"])*"|'(\\.|[^'])*')|(\w+)\s*:/g,
    function(all, string, strDouble, strSingle, jsonLabel) {
        if (jsonLabel) {
            return '"' + jsonLabel + '": ';
        }
        return all;
    });

}

(在JSFiddle上尝试)它使用一个简单的正则表达式来替换单词，用冒号表示，该词用双引号引起来.正则表达式不会在其他字符串中引用标签.

(Try on JSFiddle) It uses a simple regular expression to replace a word, followed by colon, with that word quoted inside double quotes. The regular expression will not quote the label inside other strings.

那您就可以放心了

data = JSON.parse(preprocessJSON(json));

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