Gson JSON获取结果 [英] Gson json getting the result

问题描述

我有一个像这样的json字符串:

I have a json string like this:

{
    "d": {
        "results": [
            {
                "__metadata": {
                    "uri": "http://localhost:2000",
                    "key_fields": "Accountnum",
                    "rows_affected": 0,
                    "last_autoinc": 0
                },
                "Accountnum": "9999999",
                "workphone": null,
                "name": "Smith",
                "address": "33 Main St",
                "city": "Anytown",
                "state": "FL",
                "zip": "33333",

            }
        ]
    }
}

，并且我尝试根据此处关于stackoverflow的不同问题对它进行反序列化，但是我做不到. 这是我创建的课程，我只需要一个accountnum和名称.

and I tried to deserialize it according to diffrent questions here on stackoverflow, but I can't get it right. Here is what I did I created a class, I only need the accountnum and name.

public class Result {
    @SerializedName("Accountnum")
    public String accountnumStr;

    @SerializedName("name")
    public String nameStr;    
}

我有一个带有json myresult的字符串.

I have a string with the json myresult.

Gson gson = new Gson();
Result result = gson.fromJson(myresult,Result.class);
myName.setText(result.nameStr);

我收到一个空字符串. 谢谢

I receive an empty string. Thanks

推荐答案

如果您以类对象的形式可视化JSON，则完全没有问题.想象一下，您的根对象包含类型为"D"的名为"d"的属性.类型"D"包含另一个类型结果"的结果"列表.结果包含上面的属性.这是它的图片:

If you visualize your JSON in terms of class objects then it will be no problem at all. Imagine that your root object contains a property named "d" of type "D". And type "D" contains a list of "results" of another type "Result". The result contains its properties as above. Here's the picture of it:

class RootObj {
    D d;
}

class D {
    List<Result> results;
}

class Result {
    @SerializedName("Accountnum")
    public String accountnumStr;

    @SerializedName("name")
    public String nameStr; 
}

要从JSON获取对象，请执行以下操作:

To get the objects from a JSON, you would do the following:

Gson g = new Gson();    
RootObj ro = g.fromJson(jsonString, RootObj.class);

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