PHP cURL JSON API [英] PHP cURL JSON API

问题描述

我的API文档说我需要输入以下cURL.

My API documentation says I need to enter the following cURL.

卷曲

 -H "Accept: application/json"
 -F grant_type=consumer_credentials 
 -F consumer_key=ABCDEFGHIJKLMN
 -F consumer_secret=123456789
 https://sandbox.apps.****.com/api/AccessToken 

我不知道如何处理-F位(也不知道-F代表什么！) 因此，我将它们作为JSON发布数据放入.

I've no idea what to do with the -F bits (nor what -F stands for!) So I put them in as JSON post data.

我假设-H是标题吗?

作为起点，我有一个:

$data = array(
  "grant_type" => "consumer_credentials",
  "consumer_key" => "ABCDEFGHIJKLMN",
  "consumer_secret" => "123456789"
);

$str_data = json_encode($data);

$url_send ="https://sandbox.apps.****.com/api/AccessToken";

function sendPostData($url, $post){
  $ch = curl_init($url);
  curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");  
  curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
  curl_setopt($ch, CURLOPT_POSTFIELDS,$post);
  curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1); 
  curl_setopt($ch, CURLOPT_HTTPHEADER, array('Accept: application/json'));  
  $result = curl_exec($ch);
  curl_close($ch); 
  return $result;
}

echo " " . sendPostData($url_send, $str_data);

但是我所得到的只是一个页面，指出发生了错误.它应该返回带有登录数据的JSON.

But all I get is a page that says error occurred. It should return JSON with login data.

推荐答案

正如Marc所说，我通过json而不是普通字段数据进行发送.

As Marc said, I was sending through json instead of normal field data.

我放入

foreach($data as $key=>$value) { $str_data .= $key.'='.$value.'&'; }
rtrim($str_data, '&');

代替

$str_data = json_encode($data);

它现在似乎正在工作.

谢谢

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