如何通过使用正则表达式修改其中的几个字段来创建新的JSON字符串? [英] How to create a new JSON string by modifying few fields in it using Regular Expressions?

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问题描述

我正在使用JSON,我将拥有这样的JSON-我将其称为originalJsonResponse.下面所有的json都是相同的,只是user_iduid字段可能具有这些类型的变体-

I am working with JSON and I will have JSON like this - I called it as originalJsonResponse. All the below json are same, it's just that user_id and uid field might have these types of variations -

{ "user_id": { "long": 159002376 }, "filter": { "string": "hello" } }
{ "user_id": { "string": "159002376" }, "filter": { "string": "hello" } }
{ "user_id": "159002376" , "filter": { "string": "hello" } }
{ "user_id": 159002376 , "filter": { "string": "hello" } }
{ "user_id": null, "filter": { "string": "hello" } }

{ "uid": { "long": 159002376 }, "filter": { "string": "hello" } }
{ "uid": { "string": "159002376" }, "filter": { "string": "hello" } }
{ "uid": "159002376" , "filter": { "string": "hello" } }
{ "uid": 159002376 , "filter": { "string": "hello" } }
{ "uid": null, "filter": { "string": "hello" } }

{ "filter": { "string": "hello" } }

现在,我需要从JSON中提取user_iduid字段(如果存在),并且如果这些字段的值不为null,则将这些字段的值更改为新的用户ID,然后构造另一个具有新用户ID的新json.

Now I need to extract user_id or uid field from the JSON (if it is present) and if the value of those fields are not null, then change the value of those fields to a new user id and then construct another new json with the new user id in it.

作为示例,我将newUserId作为1267818821,那么我的新json应该看起来像这样,新json应该具有与旧json相同的结构-

As an example, I will have newUserId as 1267818821, then my new json should look like this and new json should have the same structure as old json -

{ "user_id": { "long": 1267818821 }, "filter": { "string": "hello" } }
{ "user_id": { "string": "1267818821" }, "filter": { "string": "hello" } }
{ "user_id": "1267818821" , "filter": { "string": "hello" } }
{ "user_id": 1267818821 , "filter": { "string": "hello" } }
{ "user_id": null, "filter": { "string": "hello" } }

{ "uid": { "long": 1267818821 }, "filter": { "string": "hello" } }
{ "uid": { "string": "1267818821" }, "filter": { "string": "hello" } }
{ "uid": "1267818821" , "filter": { "string": "hello" } }
{ "uid": 1267818821 , "filter": { "string": "hello" } }
{ "uid": null, "filter": { "string": "hello" } }

{ "filter": { "string": "hello" } }

user_iduid字段进行混淆的最佳方法是什么?

What is the best way to do this obfuscation of user_id and uid field?

  • 我可以在这里使用正则表达式进行混淆吗?
  • 我能想到的其他方法是使用Gson解析JSON,但是如果我走这条路线,那么GSON会将传入内容读取为Double,并且读取时我的值可能会发生变化.

下面是我要进行混淆处理的方法-

Below is my method in which I want to do the obfuscation -

private static String obfuscateJson(String originalJsonResponse, String oldUserId, String newUserId) {
    // here oldUserId is 159002376 and newUserId is 1267818821

    // not sure what I should do here to construct a new json with newUserId

    String newJsonResponse = // make a new json here
    return newJsonResponse;
}

我不能在这里使用replaceAll方法(这是我开始使用的方法,意识到它将不起作用),因为我可能有另一个具有不同字段的json,并且这些字段中可能带有oldUserId编号,所以我没有要替换那些.有更好的方法吗?

I cannot use replaceAll method here (that's what I have started with and realize it will not work) since I might have another json with different fields and those fields might have oldUserId number in it so I don't want to replace those. Is there any better way of doing this?

// not a good solution
String newJsonResponse = originalJsonResponse.replaceAll(String.valueOf(oldUserId), String.valueOf(newUserId));

我想使它更通用,以便将来如果我想替换其他字段而不是user_iduid字段,那么我应该可以轻松地做到这一点.

I want to make this more generic so that in future if I want to replace some other fields instead of user_id and uid field, then I should be able to do it easily.

推荐答案

由于您在此处共享了user_id字段的所有可能的输入JSON字符串模式,因此,我想再次介绍我提出的JSON解析器解决方案之前,但现在已更新为可以处理您的不同JSON类型.

Since you've shared all the possible input JSON string patterns for the user_id field here, I would like to present again my JSON parser solution proposed before but updated to handle your different JSON types now.

public static void main(String[] args) {
    String[][] jsonInputs = new String[6][2];

    jsonInputs[0][0] = "Long-Object";
    jsonInputs[0][1] = "{ \"user_id\":{\"long\":876},\"client_id\":{\"int\":0},\"affinity\":[{\"try\":{\"long\":55787693},\"scoring\":{\"float\":0.19}},{\"try\":{\"long\":1763},\"scoring\":{\"float\":0.0114}}]}";

    jsonInputs[1][0] = "String-Object";
    jsonInputs[1][1] = "{ \"user_id\":{\"string\": \"876\"},\"client_id\":{\"int\":0},\"affinity\":[{\"try\":{\"long\":55787693},\"scoring\":{\"float\":0.19}},{\"try\":{\"long\":1763},\"scoring\":{\"float\":0.0114}}]}";

    jsonInputs[2][0] = "String";
    jsonInputs[2][1] = "{ \"user_id\": \"1267818821\" , \"filter\": { \"string\": \"hello\" } }";

    jsonInputs[3][0] = "Long";
    jsonInputs[3][1] = "{ \"user_id\": 1267818821 , \"filter\": { \"string\": \"hello\" } }";

    jsonInputs[4][0] = "Null";
    jsonInputs[4][1] = "{ \"user_id\": null , \"filter\": { \"string\": \"hello\" } }";

    jsonInputs[5][0] = "Not-Present";
    jsonInputs[5][1] = "{ \"filter\": { \"string\": \"hello\" } }";

    for (String[] json : jsonInputs) {
        System.out.println(json[0]);
        System.out.println(changeJsonString(json[1], "54321"));
        System.out.println();
    }
}

private static String changeJsonString(String originalResponse, String newId) {
    try {
        JSONObject root = new JSONObject(originalResponse);
        if (!root.isNull("user_id")) {
            Object userObj = root.get("user_id");
            if (userObj instanceof JSONObject) {
                JSONObject userId = (JSONObject) userObj;
                if (userId.has("long")) {
                    userId.put("long", Long.parseLong(newId));
                } else {
                    userId.put("string", newId);
                }
            } else if (userObj instanceof Number) {
                root.put("user_id", Long.parseLong(newId));
            } else {
                root.put("user_id", newId);
            }
        }
        return root.toString();
    } catch (JSONException e) {
        e.printStackTrace();
        return null;
    }
}

输出:

Output :

Long-Object
{"user_id":{"long":54321},"client_id":{"int":0},"affinity":[{"scoring":{"float":0.19},"try":{"long":55787693}},{"scoring":{"float":0.0114},"try":{"long":1763}}]}

String-Object
{"user_id":{"string":"54321"},"client_id":{"int":0},"affinity":[{"scoring":{"float":0.19},"try":{"long":55787693}},{"scoring":{"float":0.0114},"try":{"long":1763}}]}

String
{"filter":{"string":"hello"},"user_id":"54321"}

Long
{"filter":{"string":"hello"},"user_id":54321}

Null
{"filter":{"string":"hello"},"user_id":null}

Not-Present
{"filter":{"string":"hello"}}

这篇关于如何通过使用正则表达式修改其中的几个字段来创建新的JSON字符串?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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