如何从NSDictionary将json显示到uitextview中 [英] How to display json into uitextview from NSDictionary

问题描述

我现在整个周末都在尝试将简单的数据从mysql数据库返回到Json，再到我的应用程序中，再到漂亮的UItextview.

I'm trying now for the whole weekend to get simple data back from mysql database into Json into my app into a nice UItextview.

这是我的php代码:

this is my php code:

<?PHP

include("Connection.php");

$query="Select * from Api";

 $result=mysql_query($query,$conn);     

    while ($row1 = mysql_fetch_array($result)){  
    $users[]=$row1;
    }


$body = array();

if (!empty($users))
    $body['users'] = $users;

if (!empty($body))
    echo json_encode ($body);


    include("dbClose.php");     
?>

这是我的Xcode代码:

this is my Xcode code:

    NSURL *url = [NSURL URLWithString:JSON];
    NSLog(@"jsonreturn#########=%@",url);
    NSError *error = nil;
    NSData *jsondata = [NSData dataWithContentsOfURL:url];

    NSDictionary *dic = nil;

    if (!jsondata)
    {
        UIAlertView *alert=[[UIAlertView alloc]initWithTitle:@"Error" message:@"Data not found !!." delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
        [alert show];
        return;
    }

    //  NSLog(@"data %@",data);

    dic = [NSJSONSerialization JSONObjectWithData:jsondata options:0 error:&error];

       [_userEmail removeAllObjects];
       [_userFirst removeAllObjects];


      NSLog(@"Dictionary data %@",dic);



    for (NSDictionary *obj in [dic objectForKey:@"users"]) {

        ;
        [_userEmail addObject:[obj valueForKey:@"Email"]];


    }



   user_mail.text = [NSString stringWithFormat:@"%@", [dic valueForKey: @"Email"]];

这是Xcode中的日志，您可以在这里看到 电子邮件 ，这样您就可以看到数据解析良好:

this is the log in Xcode you can see here the email so as you can see the data parsing is good:

Dictionary data {
users =     (
            {
        0 = 1;
        1 = "dani\t";
        10 = "";
        11 = "";
        12 = 0;
        2 = "l\f)\U008f\U00d0\U00b7`\U00fcR\U0092\U00bauU\U00f2]";
        3 = dani;
        4 = dani;
        5 = "";
        6 = "";
        7 = "";
        8 = dani;
        9 = dani;
        Country = "";
        Email = "dani\t";
        "First_Name" = dani;

这是电子邮件的应用程序 UItextview 结果:

and this is the app UItextview result for the email:

(null)

所以您可以看到我的问题在这里是如何从NSDictionary获取值以文本视图的形式显示在应用程序中，我不想使用表格视图或上面的代码不是我的代码，所以请坚持为此，任何帮助都将非常感谢.

so as you can see my problem here is how to i get the value from the NSDictionary to be displayed in the app as a textview I don't want to use table view or something not such my code above so, please stick to this and any help will be great thank you all.

这是非常基本的，我刚得到我的数据库，并想要选择一些代码并将该代码返回到我的应用程序中，并返回到UItextview中，这是非常不错的，任何对我有用的方法都向我展示如何做到这一点整个周末，我都在疯狂地寻找解决方案，而在json和textview的网络上却一无所有！.

It is very basic I just got my database and want to select some code and return that code into my app into a UItextview any other way to do so will be great, every way work for me just show me how to do this I got crazy over the weekend searching for a solution for this and nothing just nothing on the web for json and textview!.

推荐答案

如果您从日志中得到的输出是这样的:

If your output from the log is this:

Dictionary data {
users =     (
        {
    0 = 1;
    1 = "dani\t";
    10 = "";
    11 = "";
    12 = 0;
    2 = "l\f)\U008f\U00d0\U00b7`\U00fcR\U0092\U00bauU\U00f2]";
    3 = dani;
    4 = dani;
    5 = "";
    6 = "";
    7 = "";
    8 = dani;
    9 = dani;
    Country = "";
    Email = "dani\t";
    "First_Name" = dani;
    }
)}

然后数据字典包含一个键为用户"的字典.

Then the dictionary of data contains a dictionary with key "users".

在用户"字典中，您有一个数组.在日志("等于数组中，"{"等于字典，表示json字符串.

Inside the "users" dictionary you have an array. In the log "(" equals array, "{" equals dictionary, for json strings.

在用户数组中，对象0有一个包含多个键的字典(0、1、10、11..Country，Email ...)

Inside the array of users, object 0 has a dictionary with several keys (0,1,10,11..Country,Email...)

因此要将键"Email"的值放在标签中，您可以执行以下操作:

So to put the value of the key "Email" in a label, you could do this:

NSDictionary *dic = [NSJSONSerialization JSONObjectWithData:jsondata options:0 error:&error];

NSArray *users = [dic objectForKey:@"users"];
NSDictionary  *firstUser = [users objectAtIndex:0];
user_mail.text = [NSString stringWithFormat:@"%@", [firstUser valueForKey: @"Email"]];

您可以迭代该数组以对用户"数组中的所有对象执行此操作，或者，如果您想要第一个或最后一个对象，则可以执行NSDictionary * firstUser = [用户firstObject]或NSDictionary * firstUser = [用户lastObject].

You could iterate the array to go do this for all objects in the "users" array, or if you know you want the first or last, you could do NSDictionary *firstUser = [users firstObject] or NSDictionary *firstUser = [users lastObject].

我希望能帮上忙.

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