从Java中的复杂JSON提取特定值 [英] Extract specific value from complex JSON in java

问题描述

我有一个有效的复杂json，我需要解析此json，并在Java中从该复杂json打印仅ak，dt和mi的值...希望您能对我有所帮助...

I have got a valid complex json and I need to parse this json and print the values of only ak, dt and mi from this complex json in java... hope you can help me...

{
  "CP": "{\"e\":{\"h\":{\"ak\":\"1c8d1d7eaa32ff3f58a882\",\"at\":\"app\"},\"c\":{\"dt\":\"MEmulator\",\"mi\":\"DD278047D56BF292F1FC16F\",\"ui\":\"m4J\/2s=\",\"av\":\"0.2\",\"pn\":\"WP\",\"pv\":\"7.10\",\"nv\":\"C# 1.1.0\",\"al\":\"en\"},\"b\":[{\"ts\":139658547,\"tz\":-400,\"s\":\"StartUpScreen\",\"et\":8,\"ev\":\"sessionStart\",\"si\":\"19477682-de55-414f-82c9-19bec331dc33\",\"tt\":{\"DaySessionStarted\":\"Tuesday\"}},{\"ts\":1319549658751,\"tz\":-400,\"s\":\"StartUpScreen\",\"et\":3,\"ev\":\"AutomaticFeedRefresh\",\"si\":\"19477682-de5ec331dc33\",\"tt\":{}},{\"ts\":1319549675609,\"tz\":-400,\"s\":\"MainScreen\",\"et\":3,\"ev\":\"MainScreen Event\",\"si\":\"19477682-de55-414f-82c9-19bec331dc33\",\"tt\":{}},{\"ts\":1319549677179,\"tz\":-400,\"s\":\"MainScreen\",\"et\":3,\"ev\":\"MainScreen Event\",\"si\":\"19477682-de55-414f-82c9-19bec331dc33\",\"tt\":{}},{\"ts\":1319549678401,\"tz\":-400,\"s\":\"MainScreen\",\"et\":3,\"ev\":\"MainScreen Event\",\"si\":\"19477682-de55-414f-82c9-19bec331dc33\",\"tt\":{}},{\"ts\":1319549679973,\"tz\":-400,\"s\":\"MainScreen\",\"et\":3,\"ev\":\"MainScreen Event\",\"si\":\"19477682-c9-19bec331dc33\",\"tt\":{}}],\"tt\":{\"OSV\":\"ME\"}}}",
  "SP": {
    "httpHeaders": {
      "x-bluecoat-via": [
        "35D3468F4D5F18"
      ],
      "content-type": [
        "application\/x-form-ur"
      ],
      "connection": [
        "Keep-Alive"
      ],
      "host": [
        "20.198.134.198:8080"
      ],
      "accept": [
        "text\/html, image\/gif, image\/jpeg, *; q=.2, *\/*; q=.2"
      ],
      "content-length": [
        "1791"
      ],
      "user-agent": [
        "Java\/1.6.0_23"
      ]
    },
    "senderIp": [
      "112.101.216.113"
    ],
    "receiveTimeStamp": "2012-06-26T06:29:36+0000"
  }
}

推荐答案

就像其他人建议的那样，那里有很多可以使用的库(npe建议看起来非常不错).另一方面，如果您只有那些简单的案例，而您实际上并不需要对JSON做其他任何事情，那么也许您所需要的只是一个正则表达式.本质上，JSON只是文本，因此您可以执行以下操作:

Like the others have suggested there are numerous libs out there that you can use (npe suggestion seems really nice). On the other hand, if you only have those simple cases and you don't really need to do anything else with JSON, maybe all you need is a regex. In essence JSON is just text, so you can do something like this:

    Pattern akPattern = Pattern.compile("ak\":\"([^\"]+)");
    Matcher matcher = akPattern.matcher(jsonAsString);

    matcher.find();
    String akValue = matcher.group(1);

    System.out.println(akValue);

这会打印出"ak"的值.

This prints out the value for "ak".

但是同样，只有在没有其他JSON要求的情况下，我才会这样做.否则，请使用JSON库.

But again, I would only do this if I didn't have any other JSON requirements. Otherwise, go with a JSON lib.

我的2美分.

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