json字符串，使用php访问不同的{}对象 [英] json string accessing different {} objects with php

问题描述

我要解析的字符串中包含一些JSON代码.我还没有使用JSON，所以这是一个简单的问题.

I have some JSON code in a string that I am trying to parse. I havent used JSON much so this is prolly a simple question.

就像:

$json_code =" 
    {
    "key1":"value",
    "key2":"value"
    },
    {
    "key3":"value",
    "key4":"value"
    }";

在尝试用php遍历所有不同对象(?-花括号的集合)时遇到问题.

Im having problems trying to loop through all of different Objects(? - the sets of curly braces) with php.

非常感谢您的帮助

谢谢， 布莱恩

推荐答案

您不能在PHP中使用这样的JSON文字.将其转换为字符串(用引号引起来)，然后使用json_decode()以类似对象的方式访问它.

You can't use a JSON literal in PHP like that. Turn it into a string (wrap it in quotes), and then use json_decode() to access it in an object like manner.

如果您希望像访问数组一样访问它，请将json_decode()的第二个参数设置为TRUE.

If you'd prefer to access it like an array, set json_decode()'s second argument to TRUE.

我看到您已将其用引号引起来-现在必须转义内部引号.

I see you have wrapped it in quotes - you must now escape the inner quotes.

要遍历它，只需对json_decode()返回的对象或数组使用foreach().

To loop through it, just use foreach() on the object or array returned from json_decode().

要使通过json_decode()解析后的结构可视化，请使用var_dump().

To visualise the structure once parsed via json_decode(), use var_dump().

您的问题是，您的JSON不正确-它有2个对象，但没有数组文字语法.您需要使用[]包装该结构.

Your problem is, your JSON is not proper - it has 2 objects, but not in array literal syntax. You need to wrap that structure with [].

看到它.

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