使用Java粘贴JSON数据 [英] Pasring JSON data using Java

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本文介绍了使用Java粘贴JSON数据的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

这是我的代码,用于从字符串json数据获取与属性名称和值关联的代码.该代码在没有错误的情况下被执行,但是我得到的结果为null.

This is my code for getting the atribute name and value assosiated with it fromstring json data .The code is getting executed without errror but i am getting the result as null.

import java.io.*;
import java.net.*;

import org.json.simple.JSONArray;
import org.json.simple.JSONObject;
import org.json.simple.parser.JSONParser;
import org.json.simple.parser.ParseException;

  public class A18 {
public static void main(String[] args) throws ParseException{
String[] out2;
String out,out1= null;
try{
    URL a=new URL("URL");
    HttpURLConnection b=(HttpURLConnection) a.openConnection();
    b.setRequestMethod("GET");
    b.setRequestProperty("Accept", "application/json");
    BufferedReader c=new BufferedReader(new InputStreamReader(b.getInputStream()));
    StringBuilder sb=new StringBuilder();



while((out=c.readLine())!=null)
 {
    sb.append(out);
 out1=sb.toString();
 }

c.close();
b.disconnect();


 JSONObject obj = new JSONObject();
    String id = obj.toJSONString("collection");
    String error = obj.toJSONString("links");
 }
        catch (Exception e)
    {

        e.printStackTrace();
        return;
    }   

    }}

推荐答案

在所有以上导入代码中,您都有import org.json.JSONObject,将其更改为import org.json.simple.JSONObject应该会有所帮助.

In your imports code above all of this you're having import org.json.JSONObject, changing that to import org.json.simple.JSONObject should help.

很可能您还需要导入其他org.json.x,您必须将其更改为org.json.simple.x.

Most probably you'll have other imports of org.json.x you'll have to change to org.json.simple.x.

这篇关于使用Java粘贴JSON数据的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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