为什么我无法使用PHP获取JSON数据? [英] Why am I unable to get JSON data using PHP?

问题描述

这是JSON文件:

//[{"id":"5417778"，"t":"TATAMTRDVR"，"e":"NSE"，"l": "329.80"，"l_fix":"329.80"，"l_cur":"Rs.329.80"，"s":"0" ，"ltt":"11:11 AM GMT + 5:30"，"lt":"Jul 26，11:11 AM GMT + 5:30"，"lt_dts" :"2016-07-26T11:11:45Z"，"c":"-0.35"，"c_fix":"-0.35"，"cp": "-0.11"，"cp_fix":"-0.11"，"ccol":"chr"，"pcls_fix":"330.15"}]

// [ { "id": "5417778" ,"t" : "TATAMTRDVR" ,"e" : "NSE" ,"l" : "329.80" ,"l_fix" : "329.80" ,"l_cur" : "Rs.329.80" ,"s": "0" ,"ltt":"11:11AM GMT+5:30" ,"lt" : "Jul 26, 11:11AM GMT+5:30" ,"lt_dts" : "2016-07-26T11:11:45Z" ,"c" : "-0.35" ,"c_fix" : "-0.35" ,"cp" : "-0.11" ,"cp_fix" : "-0.11" ,"ccol" : "chr" ,"pcls_fix" : "330.15" } ]

我的代码是

<?php
$json = file_get_contents('http://finance.google.com/finance/info?q=NSE:TATAMTRDVR');
$obj = json_decode($json);
echo $obj->id;
?>

显示的错误消息是

注意:尝试在第4行的C:\ xampp \ htdocs \ fin \ latest_stock.php中获取非对象的属性

Notice: Trying to get property of non-object in C:\xampp\htdocs\fin\latest_stock.php on line 4

推荐答案

它不是有效的json.从json响应中删除"//"，您的代码将正常工作.

It is not a valid json. Remove "// " from json response and your code will work fine.

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