JSON.net(反序列化)未类型化的属性 [英] JSON.net (de)serialize untyped property
本文介绍了JSON.net(反序列化)未类型化的属性的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
假设我有一个这样的课程:
public class Example {
public int TypedProperty { get; set; }
public object UntypedProperty { get; set; }
}
并假设有人出现并写道:
var example = new Example
{
TypedProperty = 5,
UntypedProperty = Guid.NewGuid()
}
如果我用JsonConvert.SerializeObject(example)序列化它，我会得到
{
"TypedProperty": 5,
"UntypedProperty": "24bd733f-2ade-4374-9db6-3c9f3d97b12c"
}
理想情况下，我想得到这样的东西:
{
"TypedProperty": 5,
"UntypedProperty":
{
"$type": "System.Guid,mscorlib",
"$value": "24bd733f-2ade-4374-9db6-3c9f3d97b12c"
}
}
但是TypeNameHandling在这种情况下不起作用.如何(反)序列化未类型化的属性?
解决方案
如果使用 TypeNameHandling.All 或TypeNameHandling.Auto，
那么当UntypedProperty属性将被序列化为JSON容器(对象或数组)时，Json.NET应该通过将类型信息存储在JSON文件中的"$type"属性中来正确地对其进行序列化和反序列化.但是，在UntypedProperty被序列化为JSON原语(字符串，数字或布尔值)的情况下，此操作不起作用，因为您已经注意到，JSON原语没有机会包含"$type"属性. /p>
解决方案是，当序列化具有类型object的属性的类型时，按照自定义JSON转换器，它会注入这样的包装器:
public class UntypedToTypedValueConverter : JsonConverter
{
public override bool CanConvert(Type objectType)
{
throw new NotImplementedException("This converter should only be applied directly via ItemConverterType, not added to JsonSerializer.Converters");
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
if (reader.TokenType == JsonToken.Null)
return null;
var value = serializer.Deserialize(reader, objectType);
if (value is TypeWrapper)
{
return ((TypeWrapper)value).ObjectValue;
}
return value;
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
if (serializer.TypeNameHandling == TypeNameHandling.None)
{
Console.WriteLine("ObjectItemConverter used when serializer.TypeNameHandling == TypeNameHandling.None");
serializer.Serialize(writer, value);
}
// Handle a couple of simple primitive cases where a type wrapper is not needed
else if (value is string)
{
writer.WriteValue((string)value);
}
else if (value is bool)
{
writer.WriteValue((bool)value);
}
else
{
var contract = serializer.ContractResolver.ResolveContract(value.GetType());
if (contract is JsonPrimitiveContract)
{
var wrapper = TypeWrapper.CreateWrapper(value);
serializer.Serialize(writer, wrapper, typeof(object));
}
else
{
serializer.Serialize(writer, value);
}
}
}
}
abstract class TypeWrapper
{
protected TypeWrapper() { }
[JsonIgnore]
public abstract object ObjectValue { get; }
public static TypeWrapper CreateWrapper<T>(T value)
{
if (value == null)
return new TypeWrapper<T>();
var type = value.GetType();
if (type == typeof(T))
return new TypeWrapper<T>(value);
// Return actual type of subclass
return (TypeWrapper)Activator.CreateInstance(typeof(TypeWrapper<>).MakeGenericType(type), value);
}
}
sealed class TypeWrapper<T> : TypeWrapper
{
public TypeWrapper() : base() { }
public TypeWrapper(T value)
: base()
{
this.Value = value;
}
public override object ObjectValue { get { return Value; } }
public T Value { get; set; }
}
然后使用 [JsonConverter(typeof(UntypedToTypedValueConverter))] 将其应用于您的类型:
public class Example
{
public int TypedProperty { get; set; }
[JsonConverter(typeof(UntypedToTypedValueConverter))]
public object UntypedProperty { get; set; }
}
如果您不能以任何方式修改Example类以添加此属性(您的评论该类不是我想更改的建议尽可能多)，则可以使用自定义合同解析器:
public class UntypedToTypedPropertyContractResolver : DefaultContractResolver
{
readonly UntypedToTypedValueConverter converter = new UntypedToTypedValueConverter();
// As of 7.0.1, Json.NET suggests using a static instance for "stateless" contract resolvers, for performance reasons.
// http://www.newtonsoft.com/json/help/html/ContractResolver.htm
// http://www.newtonsoft.com/json/help/html/M_Newtonsoft_Json_Serialization_DefaultContractResolver__ctor_1.htm
// "Use the parameterless constructor and cache instances of the contract resolver within your application for optimal performance."
// See also https://stackoverflow.com/questions/33557737/does-json-net-cache-types-serialization-information
static UntypedToTypedPropertyContractResolver instance;
// Explicit static constructor to tell C# compiler not to mark type as beforefieldinit
static UntypedToTypedPropertyContractResolver() { instance = new UntypedToTypedPropertyContractResolver(); }
public static UntypedToTypedPropertyContractResolver Instance { get { return instance; } }
protected override JsonObjectContract CreateObjectContract(Type objectType)
{
var contract = base.CreateObjectContract(objectType);
foreach (var property in contract.Properties.Concat(contract.CreatorParameters))
{
if (property.PropertyType == typeof(object)
&& property.Converter == null)
{
property.Converter = property.MemberConverter = converter;
}
}
return contract;
}
}
并按如下所示使用它:
var settings = new JsonSerializerSettings
{
TypeNameHandling = TypeNameHandling.Auto,
ContractResolver = UntypedToTypedPropertyContractResolver.Instance,
};
var json = JsonConvert.SerializeObject(example, Formatting.Indented, settings);
var example2 = JsonConvert.DeserializeObject<Example>(json, settings);
在两种情况下，创建的JSON都类似于:
{ "TypedProperty": 5, "UntypedProperty": { "$type": "Question38777588.TypeWrapper`1[[System.Guid, mscorlib]], Tile", "Value": "e2983c59-5ec4-41cc-b3fe-34d9d0a97f22" } }
Suppose I have a class like this:
public class Example {
public int TypedProperty { get; set; }
public object UntypedProperty { get; set; }
}
And suppose someone comes along and writes:
var example = new Example
{
TypedProperty = 5,
UntypedProperty = Guid.NewGuid()
}
If I serialize this with JsonConvert.SerializeObject(example), I get
{
"TypedProperty": 5,
"UntypedProperty": "24bd733f-2ade-4374-9db6-3c9f3d97b12c"
}
Ideally, I'd like to get something like this:
{
"TypedProperty": 5,
"UntypedProperty":
{
"$type": "System.Guid,mscorlib",
"$value": "24bd733f-2ade-4374-9db6-3c9f3d97b12c"
}
}
But TypeNameHandling doesn't work in this scenario. How can I (de)serialize an untyped property?
解决方案
If you serialize your class with TypeNameHandling.All or TypeNameHandling.Auto,
then when the UntypedProperty property would be serialized as a JSON container (either an object or array) Json.NET should correctly serialize and deserialize it by storing type information in the JSON file in a "$type" property. However, in cases where UntypedProperty is serialized as a JSON primitive (a string, number, or Boolean) this doesn't work because, as you have noted, a JSON primitive has no opportunity to include a "$type" property.
The solution is, when serializing a type with a property of type object, to serialize wrappers classes for primitive values that can encapsulate the type information, along the lines of this answer. Here is a custom JSON converter that injects such a wrapper:
public class UntypedToTypedValueConverter : JsonConverter
{
public override bool CanConvert(Type objectType)
{
throw new NotImplementedException("This converter should only be applied directly via ItemConverterType, not added to JsonSerializer.Converters");
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
if (reader.TokenType == JsonToken.Null)
return null;
var value = serializer.Deserialize(reader, objectType);
if (value is TypeWrapper)
{
return ((TypeWrapper)value).ObjectValue;
}
return value;
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
if (serializer.TypeNameHandling == TypeNameHandling.None)
{
Console.WriteLine("ObjectItemConverter used when serializer.TypeNameHandling == TypeNameHandling.None");
serializer.Serialize(writer, value);
}
// Handle a couple of simple primitive cases where a type wrapper is not needed
else if (value is string)
{
writer.WriteValue((string)value);
}
else if (value is bool)
{
writer.WriteValue((bool)value);
}
else
{
var contract = serializer.ContractResolver.ResolveContract(value.GetType());
if (contract is JsonPrimitiveContract)
{
var wrapper = TypeWrapper.CreateWrapper(value);
serializer.Serialize(writer, wrapper, typeof(object));
}
else
{
serializer.Serialize(writer, value);
}
}
}
}
abstract class TypeWrapper
{
protected TypeWrapper() { }
[JsonIgnore]
public abstract object ObjectValue { get; }
public static TypeWrapper CreateWrapper<T>(T value)
{
if (value == null)
return new TypeWrapper<T>();
var type = value.GetType();
if (type == typeof(T))
return new TypeWrapper<T>(value);
// Return actual type of subclass
return (TypeWrapper)Activator.CreateInstance(typeof(TypeWrapper<>).MakeGenericType(type), value);
}
}
sealed class TypeWrapper<T> : TypeWrapper
{
public TypeWrapper() : base() { }
public TypeWrapper(T value)
: base()
{
this.Value = value;
}
public override object ObjectValue { get { return Value; } }
public T Value { get; set; }
}
Then apply it to your type using [JsonConverter(typeof(UntypedToTypedValueConverter))]:
public class Example
{
public int TypedProperty { get; set; }
[JsonConverter(typeof(UntypedToTypedValueConverter))]
public object UntypedProperty { get; set; }
}
If you cannot modify the Example class in any way to add this attribute (your comment The class isn't mine to change suggests as much) you could inject the converter with a custom contract resolver:
public class UntypedToTypedPropertyContractResolver : DefaultContractResolver
{
readonly UntypedToTypedValueConverter converter = new UntypedToTypedValueConverter();
// As of 7.0.1, Json.NET suggests using a static instance for "stateless" contract resolvers, for performance reasons.
// http://www.newtonsoft.com/json/help/html/ContractResolver.htm
// http://www.newtonsoft.com/json/help/html/M_Newtonsoft_Json_Serialization_DefaultContractResolver__ctor_1.htm
// "Use the parameterless constructor and cache instances of the contract resolver within your application for optimal performance."
// See also https://stackoverflow.com/questions/33557737/does-json-net-cache-types-serialization-information
static UntypedToTypedPropertyContractResolver instance;
// Explicit static constructor to tell C# compiler not to mark type as beforefieldinit
static UntypedToTypedPropertyContractResolver() { instance = new UntypedToTypedPropertyContractResolver(); }
public static UntypedToTypedPropertyContractResolver Instance { get { return instance; } }
protected override JsonObjectContract CreateObjectContract(Type objectType)
{
var contract = base.CreateObjectContract(objectType);
foreach (var property in contract.Properties.Concat(contract.CreatorParameters))
{
if (property.PropertyType == typeof(object)
&& property.Converter == null)
{
property.Converter = property.MemberConverter = converter;
}
}
return contract;
}
}
And use it as follows:
var settings = new JsonSerializerSettings
{
TypeNameHandling = TypeNameHandling.Auto,
ContractResolver = UntypedToTypedPropertyContractResolver.Instance,
};
var json = JsonConvert.SerializeObject(example, Formatting.Indented, settings);
var example2 = JsonConvert.DeserializeObject<Example>(json, settings);
In both cases the JSON created looks like:
{ "TypedProperty": 5, "UntypedProperty": { "$type": "Question38777588.TypeWrapper`1[[System.Guid, mscorlib]], Tile", "Value": "e2983c59-5ec4-41cc-b3fe-34d9d0a97f22" } }
这篇关于JSON.net(反序列化)未类型化的属性的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
查看全文
