Servlet和JSP.一个简单的要求? [英] Servlets and JSPs. A simple request?
问题描述
我已经设置了许多Java Server Page，并且我想通过添加Process Servlet(扩展HttpServlet)来使用Controller/View系统.
I have a number of Java Server Pages set up already and I would like to use a Controller/View system by adding a Process Servlet (which extends HttpServlet).
我只想在ProcessServlet添加一些属性后基本上按常规处理所请求的JSP.
I just want to basically process the requested JSPs as normal after the ProcessServlet has added some attributes.
说我所有的JSP都位于一个名为/content/的目录中，并且我的web.xml文件具有一个将/content/*.jsp映射到我的ProcessServlet的规则
Say all my JSPs are in a directory called /content/ and my web.xml file has a rule to map /content/*.jsp to my ProcessServlet
我一直无法找到将所有JSP移到不同目录(/content-JSPs/)的方法，这样就可以将它们分派到而不用无休止地遍历ProcessServlet了.
I have not been able to find a way short of moving all of my JSPs into a different directory (/content-JSPs/) so that they can be dispatched to without having to go through the ProcessServlet endlessly.
是否有一种方法可以基本上将#forward()(其他方法?)分派给所请求的JSP，而无需再次使其通过ProcessServlet?
Is there a way to basically dispatch#forward() (some other method?) to the requested JSP without having it go through the ProcessServlet again?
很难相信这种缺乏灵活性的存在.为什么Servlet不能仅充当对JSP的传递?
It's a bit hard to believe that this lack of flexibility exists. Why can't the Servlet just act as a pass through to the JSP?
我的目标是设置所有内容，以便Web服务器不必为所有JSP拥有单独的目录，而为其他所有内容(即CSS，JavaScript和图像)拥有另一个目录.我想保持目录结构(和URL结构)不变.
My goal here is to set everything up so that the web server does not have to have a separate directory for all JSPs and another directory for everything else i.e. CSS, JavaScript and images. I would like to keep the directory structure (and URL structure) as it is.
推荐答案
将它们放在/WEB-INF文件夹中.这也有效地使JSP隐藏在直接访问之外.您只需更改RequestDispatcher#forward()调用即可在路径中包含/WEB-INF.
Put them in /WEB-INF folder. This also effectively hides JSPs away from direct access. You only need to change the RequestDispatcher#forward() call to include /WEB-INF in the path.
request.getRequestDispatcher("/WEB-INF/content" + request.getPathInfo()).forward(request, response);
请注意，/content/*.jsp的URL模式在语法上无效.它应该是/content/*.也许您也确实使用过.要跳过静态资源，例如images/css/JS，您不应将其放在/content中，而应放在例如/resources，/static等中.
Please note that the URL pattern of /content/*.jsp is syntactically invalid. It should be /content/*. Perhaps you have also really used that. To skip static resources like images/css/JS, you should just not put them in /content, but in for example /resources, /static, etc.
- Design Patterns web based applications
- Hidden features of JSP/Servlet
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