java.lang.IllegalStateException:使用jsp:include包含HTML文件时，在提交响应后无法转发 [英] java.lang.IllegalStateException: Cannot forward after response has been committed while including HTML files using jsp:include

问题描述

当<jsp:include>用于包含HTML文件时DispatcherServlet正在抛出

When <jsp:include> is used for including HTML file DispatcherServlet is throwing

java.lang.IllegalStateException: Cannot forward after response has been committed

我有一个servlet:

I have one servlet:

<servlet-mapping>
    <servlet-name>web</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

在其中，我启用了Spring MVC批注，并为没有控制器的JSP文件提供了处理程序映射和适配器(将旧的webapp转换为Spring).并且我已经在该Servlet中启用了DefaultServletHttpRequestHandler.

In it, I have enabled Spring MVC annotations and have handler mapping and adapter for JSP files without controllers (converting old webapp to Spring). And I have enabled DefaultServletHttpRequestHandler in this Servlet.

有什么想法在包含html文件时如何避免IllegalStateException?

Any idea how to avoid that IllegalStateException when including html files?

推荐答案

因此，如果让spring处理所有html文件，则由于无法处理html包含内容，因此在jsp:include上它总是会失败.

So if you let spring handle all html files, it will always fail on jsp:include because spring cannot handle html includes.

对我而言，最好的解决方法是将html文件保留在默认servlet上.

Best way around this for me was to leave html files on default servlet.

<servlet-mapping>
    <servlet-name>default</servlet-name>
    <url-pattern>*.html</url-pattern>
    <url-pattern>*.htm</url-pattern>
</servlet-mapping>

并在DispatcherServlet上保持静止.

 <servlet>
    <servlet-name>web</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
    <servlet-name>web</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

这绝对不是最佳解决方案，但是直到我将所有jsps(约1000个)转换为mvc和类似tile的东西，这才是我看到它工作的唯一方法.

This is definitely not a best solution, but until I convert all jsps (around 1000 of them) to mvc and something like tiles this is the only way I can see it working.

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