在不同的布局按钮状态在一个活动？ [英] Button state across different layouts in one activity?

问题描述

我有2个按钮在同一活动2的布局之间进行切换：点击Button1的布局1，这是不言而喻2（使用的setContentView）布局。在布局2，点击按钮2，它可以追溯到布局1。然后BUTTON1不再响应OnClickListener。我看着输入事件但还是没能弄明白。发生了什么，以及如何解决它？

在此先感谢！

 按钮submitBtn;
按钮backBtn;
submitBtn =（按钮）findViewById（R.id.button1）; //在布局1
backButn =（按钮）findViewById（R.id.button2）; //在布局2
submitBtn.setOnClickListener（新View.OnClickListener（）{        @覆盖
        公共无效的onClick（视图v）{
          的setContentView（R.layout.layout2）;
                    }
    }）;
backBtn.setOnClickListener（新View.OnClickListener（）{        @覆盖
        公共无效的onClick（视图v）{
          的setContentView（R.layout.layout1）;
                   }
    }）;
 

解决方案

您应该在切换布局时，要呼叫的setContentView 旧观点重新分配听众，原因被破坏，并创建新的组件。

I have 2 buttons to switch between 2 layouts in the same activity: clicking button1 on layout1, it goes to layout 2 (using setContentView). On layout2, clicking button2, it goes back to layout1. Then button1 is no longer responding OnClickListener. I looked into "Input Events" but still couldn't figure it out. What happened and how to fix it?

Thanks in advance!

Button submitBtn;
Button backBtn;
submitBtn = (Button)findViewById(R.id.button1); //on layout1
backButn = (Button)findViewById(R.id.button2);  //on layout2
submitBtn.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {
          setContentView(R.layout.layout2);
                    }
    });
backBtn.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {
          setContentView(R.layout.layout1);
                   }
    });

解决方案

You should re-assign listeners when you switch layout, cause when you're calling setContentView old view is destroyed, and new components are created.

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