刀片条件语句 [英] Blade conditional statements

问题描述

我有几种型号.每个模型都有一个创建和编辑页面.如果尚未创建模型，则需要显示其创建页面.如果已创建，则需要显示其编辑页面.

I have several models. Each model has a create and edit page. If the model has not been created yet, I need to display its create page. If it has been created, I need to show its edit page.

到目前为止，我有这个可行的方法

So far I have this which works

<div class="panel-group" id="accordion">
    @if (is_null($project->projectType))
        @include ('projects.partials.projectTypesCreate')
    @else
        @include ('projects.partials.projectTypesEdit')
    @endif

    @if (is_null($project->projectData))
        @include ('projects.partials.projectDataCreate')
    @else
        @include ('projects.partials.projectDataEdit')
    @endif

    @if (is_null($project->projectTesting))
        @include ('projects.partials.projectTestingCreate')
    @else
        @include ('projects.partials.projectTestingEdit')
    @endif
</div>

在我看来，对于许多有条件的声明来说，以上内容并不是最漂亮的.更糟糕的是，我需要按顺序显示事物.我的意思是，如果projectType为null， 仅应显示projectTypesCreate.如果不为null.应该显示projectTypesEdit和projectDataCreate，依此类推.

Now, the above is not the prettiest, to many conditional statements in my opinion. What makes this worse is the fact that I need to display things in order. By this I mean that if projectType is null, only projectTypesCreate should be displayed. If it is not null. projectTypesEdit and projectDataCreate should be displayed, and so on.

要做到这一点，我可能会做类似的事情

To accomplish this I could potentially do something like so

@if (is_null($project->projectType))
    @include ('projects.partials.campaignTypes')
@else
    @include ('projects.partials.campaignTypesEdit')
@endif

@if (!is_null($project->projectType) && is_null($project->projectData))
    @include ('projects.partials.projectDataCreate')
@else
    @include ('projects.partials.projectDataEdit')
@endif

@if (!is_null($project->projectData) && is_null($project->projectTesting))
    @include ('projects.partials.projectTestingCreate')
@else
    @include ('projects.partials.projectTestingEdit')
@endif

再一次，它变得有点笨拙，并且我所需的信息也不准确，因为条件失败时将显示编辑页面.

Once again though, it is getting a bit clunky and it is not accurate as to what I need because the edit page will display when the condition fails.

因此，实际上我只是在寻求一些有关如何最好地处理这种情况的建议.我需要确定要为每种模型显示的视图，同时要顺序显示视图.

So really I am just after some advice as to how to best handle this situation. I need to determine what view to display for each model, whilst at the same time displaying views sequentially.

谢谢

推荐答案

创建一个单独的$action变量，该变量保存要执行的操作，然后在@include语句中使用该变量:

Create a single $action variable that holds the action you want to do, then use that in your @include statements:

<div class="panel-group" id="accordion">
    @php($action = is_null($project->projectType) ? 'Create' : 'Edit')

    @include('projects.partials.projectTypes'.$action)
    @include('projects.partials.projectData'.$action)
    @include('projects.partials.projectTesting'.$action)
</div>

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