laravel渴望加载以最小化查询 [英] laravel eager loading to minimize queries

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问题描述

我正在将laravel与DDD模式一起使用,这是我的代码来为网站制作一些分析报告...

I am using laravel with DDD Pattern and here is my code to make some analytics report for website...

我来自存储库的代码...

//Abstract Entity
  public function getFirstBy($key, $value, array $with = array())
  {
    return $this->repository->getFirstBy($key, $value, $with);
  }


//Link Entity
$link = parent::getFirstBy('hash', $data['hash'], ['visits']);


//prepare report
          $report = [];

          //get dates difference
          $date1 = new \DateTime($data['from']);
          $date2 = new \DateTime($data['to']);
          $date_diff = $date2->diff($date1)->format("%a");

          $time_visits = $link->visits()->whereRaw('DATE(created_at) BETWEEN ? AND ?', array($date1, $date2))->groupBy('created_at')->orderBy('created_at', 'ASC')->get();

          //Total Visits
          $report['total_visits'] = $time_visits->count();

    //country visits
          $country_visits = $link->visits()->whereRaw('DATE(created_at) BETWEEN ? AND ?', array($date1, $date2))->orderBy('country_iso', 'ASC')->groupBy('country_iso')->get();

    //referrers
          $referer_visits = $link->visits()->whereRaw('DATE(created_at) BETWEEN ? AND ?', array($date1, $date2))->where('source', '!=', '')->orderBy('source', 'ASC')->groupBy('source')->get();

    //browsers
          $browser_visits = $link->visits()->whereRaw('DATE(created_at) BETWEEN ? AND ?', array($date1, $date2))->where('browser', '!=', '')->orderBy('browser', 'ASC')->groupBy('browser')->get();

    //os
          $os_visits = $link->visits()->whereRaw('DATE(created_at) BETWEEN ? AND ?', array($date1, $date2))->where('os', '!=', '')->orderBy('os', 'ASC')->groupBy('os')->get();


The code is working perfectly fine but executing 6 mysql queries which could be a big problem for larger usage... 

**sql queries dump...**

    select * from `link_visits` where `link_visits`.`link_id` = '4' and DATE(created_at) BETWEEN '2014-09-15 00:00:00' AND '2014-09-17 00:00:00' group by `created_at` order by `created_at` asc

    select * from `link_visits` where `link_visits`.`link_id` = '4' and DATE(created_at) BETWEEN '2014-09-15 00:00:00' AND '2014-09-17 00:00:00' group by `country_iso` order by `country_iso` asc

    select count(*) as total_visits, medium from `link_visits` where `link_visits`.`link_id` = '4' and DATE(created_at) BETWEEN '2014-09-15 00:00:00' AND '2014-09-17 00:00:00' group by `medium` order by `medium` asc

    select * from `link_visits` where `link_visits`.`link_id` = '4' and DATE(created_at) BETWEEN '2014-09-15 00:00:00' AND '2014-09-17 00:00:00' and `source` != '' group by `source` order by `source` asc

    select * from `link_visits` where `link_visits`.`link_id` = '4' and DATE(created_at) BETWEEN '2014-09-15 00:00:00' AND '2014-09-17 00:00:00' and `browser` != '' group by `browser` order by `browser` asc

    select * from `link_visits` where `link_visits`.`link_id` = '4' and DATE(created_at) BETWEEN '2014-09-15 00:00:00' AND '2014-09-17 00:00:00' and `os` != '' group by `os` order by `os` asc

Please suggest some good ways to optimize it better. thanks, i really need advanced help with this.

推荐答案

您可以在ex的关系中使用子查询.

you can use sub query in the relations for ex.

假设$ link是您的模型对象

assuming $link is you model object

$link->with(['Visits'=>function($q){
       $q->whereRaw('DATE(created_at) BETWEEN ? AND ?', array($date1,$date2))->where('browser', '!=', '')->orderBy('browser', 'ASC')->groupBy('browser');
}])->get();

内部查询将相应地过滤所有记录,并且内部查询仅适用于Visits模型

the inner query will filter all your records accordingly and the inner query will apply only in the Visits model

我的建议是先不进行任何过滤就获取所有记录,然后使用filter()方法将其过滤到集合对象中!因此它将仅使用1个查询进行访问以获取所有记录,然后仅使用filter()方法对其进行重新排列

my suggestion is first fetch all the records without any filteration and then filter them in the object of collection with filter() method! so it will use only 1 query for visit to fetch all records then you only rearrange them using filter() method

这篇关于laravel渴望加载以最小化查询的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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