Laravel Guzzle从页面获取目的地和预定时间 [英] Laravel Guzzle getting destination and due time from a page

问题描述

我希望我的网站从此页面抓取信息beta.tfgm.com/public-transport/tram/stops/oldham-central-tra‌m，尤其是我要从该网站抓取目的地和到期时间，并提供我的输出.

I want my website to scrape information from this page beta.tfgm.com/public-transport/tram/stops/oldham-central-tra‌​m and in particular I want to scrape destination and due time from that website and give me an output.

此刻，我的控制器如下所示:

At this moment my controller looks like this:

function guzzle(){
$client = new \GuzzleHttp\Client();
$results = $client->get('https://beta.tfgm.com/public-transport/tram/stops/oldham-central-tram');
//$result->getBody();
//return view('hello')->with('results', $results);
//dd($result);
$results->getBody()->getContents();
dd($results);
return view('hello');
}

输出为:

Response {#190 ▼
  -reasonPhrase: "OK"
  -statusCode: 200
  -headers: array:8 [▼
    "Content-Security-Policy" => array:1 [▶]
    "Content-Type" => array:1 [▶]
    "Date" => array:1 [▶]
    "ETag" => array:1 [▶]
    "X-Content-Security-Policy" => array:1 [▶]
    "X-WebKit-CSP" => array:1 [▶]
    "Content-Length" => array:1 [▶]
    "Connection" => array:1 [▶]
  ]
  -headerNames: array:8 [▼
    "content-security-policy" => "Content-Security-Policy"
    "content-type" => "Content-Type"
    "date" => "Date"
    "etag" => "ETag"
    "x-content-security-policy" => "X-Content-Security-Policy"
    "x-webkit-csp" => "X-WebKit-CSP"
    "content-length" => "Content-Length"
    "connection" => "Connection"
  ]
  -protocol: "1.1"
  -stream: Stream {#188 ▶}
}

但是我如何访问特定的html类，从中获取信息并将其输出到我的页面上?

However how can I access specific html class, scrape information from it and output it on my page?

推荐答案

dd在这里对您没有用，请尝试以下方法:

dd is not useful for you here, try this :

$client = new \GuzzleHttp\Client();
$results = $client->get('https://beta.tfgm.com/public-transport/tram/stops/oldham-central-tram');

print_r($results->getBody()->getContents()); // The HTML content

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