sed提取数字组 [英] sed extracting group of digits

问题描述

我尝试提取下面给出的数字，但屏幕上没有任何打印内容

I have tried to extract a number as given below but nothing is printed on screen:

echo "This is an example: 65 apples" | sed -n  's/.*\([0-9]*\) apples/\1/p'

但是，如果两个数字分别如下匹配，我将得到'65':

However, I get '65', if both digits are matched separately as given below:

echo "This is an example: 65 apples" | sed -n  's/.*\([0-9][0-9]\) apples/\1/p'
65

我该如何匹配一个数字，使得我不知道要提取的数字中的位数，例如可以用2344代替65?

How can I match a number such that I don't know the number of digits in a number to be extracted e.g. it can be 2344 in place of 65?

推荐答案

$ echo "This is an example: 65 apples" | sed -r  's/^[^0-9]*([0-9]+).*/\1/'
65

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