如何在Python中获取用于手动锁定机制的进程PID? [英] How to get process PID for manual lock mechanism in Python?

问题描述

我想在Python中建立一种简单的锁定机制，而不必依赖现有的库进行锁定(即fcntl以及其他可能的库)

I would like to make a simple locking mechanism in Python without having to rely on the existing libraries for locking (namely fcntl and probably others)

我已经有一个小存根，但经过一番搜索后，我找不到如何手动创建锁定文件并将进程PID放入其中的良好答案.这是我的存根:

I already have a small stub, but after searching for a bit I couldn't find a good on answer on how to manually create the lock file and put the process PID inside. Here is my stub:

dir_name = "/var/lock/mycompany"
file_name = "myapp.pid"
lock = os.path.join(dir_name, file_name)

if os.path.exists(lock):
    print >> sys.stderr, "already running under %s, exiting..." % lock
    # display process PID contained in the file, not relevant to my question
    sys.exit(ERROR_LOCK)
else:
    # create the file 'lock' and put the process PID inside

如何获取当前的进程PID并将其放在lock文件中?我考虑过要查看/proc文件系统，但是对于这样一个简单的任务来说，这似乎有点太多了.

How can I get the current process PID and put it inside the lock file? I thought about looking at /proc filesystem but that seems a bit too much for such a simple task.

谢谢.

推荐答案

open(lock, 'w').write(os.getpid())

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