platform.linux_distribution()已过时-有哪些替代方案? [英] platform.linux_distribution() deprecated - what are the alternatives?

问题描述

从Python> 3.5开始，不推荐使用函数platform.linux_distribution(): https://docs.python.org/3.5/library/platform.html #platform.linux_distribution

As of Python >3.5 the function platform.linux_distribution() is being deprecated: https://docs.python.org/3.5/library/platform.html#platform.linux_distribution

有什么可以直接替代的吗?

Is there anything that directly replaces it?

不幸的是，由于我是在docker容器中构建的，所以platform.uname()无法提供所需的信息，这将返回主机的详细信息而不是映像.

Unfortunately for me, platform.uname() doesn't yield the information I need since I'm building in a docker container and this returns the details of the host machine not the image.

尤其是:我正在构建一个可移植的linux发行版( https://www .python.org/dev/peps/pep-0513/)，并希望在规范的CentOS 5.11发行版上对其进行测试.我正在寻找一种识别操作系统的简单方法，以便可以识别/标记构建结果.

In particular: I'm building a portable linux distribution (https://www.python.org/dev/peps/pep-0513/) and want to test it on the canonical CentOS 5.11 distribution. I'm looking for a simple way to identify the OS so I can identify/tag the build results.

推荐答案

根据此，将从Python 3.7开始弃用platform.linux_distribution().我可以确认它确实存在于3.6中.该链接推荐使用发行版包作为替代.

According to this, the platform.linux_distribution() will be deprecated beginning with Python 3.7. I can confirm that it is indeed present in 3.6. The link recommend the distro package as the alternative.

安装软件包后，您可以

import distro
distro.linux_distribution()

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