linux查找名称中带有可选字符的文件 [英] linux find files with optional character in their name

问题描述

假设我有两个文件:ac和abc.我想找到一个正则表达式来匹配两个文件.通常，我希望以下正则表达式能够正常工作，但它永远不会起作用:

suppose I have two files: ac and abc. I want to find a regex to match both files. Normally I would expect the following regex to work, but it never does:

find ./ -name ab?c

我已经尝试过转义或不转问问号，这似乎从来没有奏效.通常在我找到的正则表达式文档中； ?表示:前一个字符重复0或1次，但是find似乎不理解这一点.

I have tried escaping or not the questionmark, this never seems to work. Normally in the regex documentations I have found; ? means: previous character repeated 0 or 1 times, but find doesn't seem to understand this.

我已经在两个不同的查找版本上进行了尝试:GNU查找版本4.2.31和 查找(GNU findutils)4.6.0

I have tried this on two different find versions: GNU find version 4.2.31 and find (GNU findutils) 4.6.0

PS:这适用于*，但是我特别想只匹配一个可选字符.

PS: this works with *, but I specifically would like to match just one optional character.

find ./ -name a*c

给予

./ac
./abc

推荐答案

传递给-name的表达式不是正则表达式，而是全局表达式. (单个)全局表达式不能用于您的用例，但是您可以使用-regex:

The expression passed to -name is not a regex, it is a glob expression. A (single) glob expression can't be used for your use case but you can use regular expressions using -regex:

find -regex '.*/ab?c'

顺便说一句，默认的正则表达式语言是Emacs样式，如下所述: https://www.emacswiki. org/emacs/RegularExpression .您可以使用-regextype更改正则表达式语言.

Btw, the default regular expression language is Emacs Style as explained here : https://www.emacswiki.org/emacs/RegularExpression . You can change the regex language using -regextype.

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