获取导致404的请求页面的URL [英] Get URL of page requested that caused a 404

问题描述

如何获取导致404错误的请求页面的URL?

How would I get the URL of the page that was requested that caused the 404 error?

例如，我输入 http://example.com/路径/确实/不/存在/index.jsp 我已经有一个自定义的404页面，但是如何检索上面提到的URL，以便可以显示类似"URL

For example, I type I go to http://example.com/path/does/not/exist/index.jsp I already have a custom 404 page but how would I go about retrieving the URL mentioned above so that I can display it with a message similar to "The url http://example.com/path/does/not/exist/index.jsp does not exist"?

推荐答案

如果使用Forward进入错误页面，则可以通过

If forward was used to go to the error page, you can obtain the original request URL by

request.getAttribute("javax.servlet.forward.request_uri")

或通过EL

${requestScope['javax.servlet.forward.request_uri']}

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