如何运行一个jsp程序? [英] How to run a jsp program?
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问题描述
这是一个简单的jsp程序.有人可以告诉我运行它的步骤吗?
This is a simple jsp program.can anyone tell me the steps to run it?
<%--
Document : helloworld
Created on : Dec 20, 2010, 10:20:48 PM
Author : eswar
--%>
<%@page contentType="text/html" pageEncoding="UTF-8"%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>JSP Page</title>
</head>
<body>
<p> Hi, <h3><%="Hello!" %></h3></p>
<p>You successfully run a simple jsp program.</p>
<p>Learn More concept about jsp.</p>
</body>
</html>
推荐答案
您需要一个JSP/Serlvet容器，该容器可以为您服务JSP页面.有许多可用的JSP/Servlet容器并已使用，但最常用的是 Apache Tomcat .
You need a JSP/Serlvet container that can server JSP pages for you. There a number of JSP/Servlet containers available and used but the most commonly used is Apache Tomcat.
要设置Tomcat
- 只需下载并将其解压缩到任何文件夹中
- 接下来，将您的应用程序放置在webapps文件夹中
- 启动服务器.
- 打开浏览器并浏览到URL
http://localhost:8080，它应该会打开tomcat的默认页面 - 将您的应用程序打包为war，并将其放置在tomcat的webapps文件夹中
- 现在访问URL
http://localhost:8080/YourApplicatioContext/path/to/jspFile，您将看到JSP文件正在编译并在浏览器中提供服务
- simply download it and extract it into any folder
- Next, place your application inside the webapps folder
- Start the server.
- Open your browser and browse to URL
http://localhost:8080, it should open the tomcat's default page - Package your application as war, and place it in the webapps folder of tomcat
- Now Access the URL
http://localhost:8080/YourApplicatioContext/path/to/jspFileand you will see your JSP file being compiled and served in the browser
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