如何在julia中将Array {Array {Float64，1}，1}转换为Matrix? [英] How to convert Array{Array{Float64, 1}, 1} to Matrix in julia?

问题描述

假设我有这种输入:

> [[0.8681299566762923,-0.3472589826095631], [3.2300860990307445,3.3731249077464946]]

如何将其转换为更令人愉快的类型(如Matrix(知道尺寸))?

How can I convert it to more pleasant type like Matrix (knowing dimensions)?

推荐答案

您可以使用splatting(...)和hcat来获得所需的信息:

You can use splatting (...) and hcat to get what you are after:

julia> a = Vector[[0.8681299566762923,-0.3472589826095631], [3.2300860990307445,3.3731249077464946]]
2-element Array{Array{T,1},1}:
 [0.8681299566762923,-0.3472589826095631]
 [3.2300860990307445,3.3731249077464946]

julia> hcat(a...)
2x2 Array{Float64,2}:
  0.86813   3.23009
 -0.347259  3.37312

或者，如果您希望将堆栈停止为行而不是列，则可以执行以下操作:

Or if you wanted stop stack as rows instead of columns you could do the following:

julia> vcat(map(x->x', a)...)
2x2 Array{Float64,2}:
 0.86813  -0.347259
 3.23009   3.37312

我不建议逐行构建Matrix，因为这与Julia的

I don't recommend building a Matrix row by row as that is in conflict with Julia's column major array layout. For larger matrices it is actually more efficient to stack as columns and transpose the output:

julia> a2 = Vector{Float64}[rand(10) for i=1:5000];

julia> stackrows1{T}(a::Vector{Vector{T}}) = vcat(map(transpose, a)...)::Matrix{T}
stackrows1 (generic function with 2 methods)

julia> stackrows2{T}(a::Vector{Vector{T}}) = hcat(a...)'::Matrix{T}
stackrows2 (generic function with 2 methods)

julia> stackrows1(a2) == stackrows2(a2)  # run once to compile and make sure functions do the same thing
true

julia> @time for i=1:100 stackrows1(a2); end
elapsed time: 0.142792896 seconds (149 MB allocated, 7.85% gc time in 7 pauses with 0 full sweep)

julia> @time for i=1:100 stackrows2(a2); end
elapsed time: 0.05213114 seconds (88 MB allocated, 12.60% gc time in 4 pauses with 0 full sweep)

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