在Julia中构建非默认构造函数 [英] Building a non-default constructor in Julia

问题描述

如何在Julia中使用少于输入值的输入构建构造函数?我有一个Int64数字数组，其中每个数字代表24个布尔值.最好的情况是，我可以发送数组并返回具有每个组件数组的复合类型.这是我尝试过的代码.

How do I build a constructor in Julia with fewer inputs than values? I have an Int64 array of numbers where each number represents 24 boolean values. The best situation would be that I could send in the array and get back a composite type with arrays of each component. Here is the code I've tried.

type Status
   Valve1::Array{Bool}
   Valve2::Array{Bool}
   Valve3::Array{Bool}
   Valve4::Array{Bool}
   Valve5::Array{Bool}
   Valve6::Array{Bool}
   Valve7::Array{Bool}
   Valve8::Array{Bool}

   # Constructor for Status type
   function Status(vals::Array{Int64})
   l = int64(length(vals))

   Valve1 = Array(Bool,l)
   Valve2 = Array(Bool,l)
   Valve3 = Array(Bool,l)
   Valve4 = Array(Bool,l)
   Valve5 = Array(Bool,l)
   Valve6 = Array(Bool,l)
   Valve7 = Array(Bool,l)
   Valve8 = Array(Bool,l)

   # Parse Inputs
   for i=1:l
      # Byte 1
      Valve1[i] = vals[i] & 2^(1-1) > 0
      Valve2[i] = vals[i] & 2^(2-1) > 0
      Valve3[i] = vals[i] & 2^(3-1) > 0
      Valve4[i] = vals[i] & 2^(4-1) > 0
      Valve5[i] = vals[i] & 2^(5-1) > 0
      Valve6[i] = vals[i] & 2^(6-1) > 0
      Valve7[i] = vals[i] & 2^(7-1) > 0
      Valve8[i] = vals[i] & 2^(8-1) > 0
   end # End of conversion

   new(Valve1,Valve2,Valve3,Valve4,Valve5,Valve6,Valve7,Valve8)

   end # End of constructor
end # End of type

这将导致no method convert(Type{Bool},Array{Bool,1})错误.我试图用statuses = Status(StatusW)实例化它，其中StatusW是一个Int64值数组.

This results in a no method convert(Type{Bool},Array{Bool,1}) error. I tried to instantiate it with statuses = Status(StatusW) where StatusW is an Int64 array of values.

有用的参考文献:类型和推荐答案

声明必须如下.

Valve1::Vector{Bool}

另一个引起我困惑的因素是new(Valve1,...)应该是构造函数中的最后一件事.我在new(Valve1,...)之后添加了调试println()行，导致该类型返回 Nothing .

Another factor contributing to my confusion was that new(Valve1,...) should be the last thing in the constructor. I had added debugging println()lines after the new(Valve1,...) causing the type to return Nothing.

Julia Google网上论坛上的Tim Holy提供了解决方案.

Tim Holy on the Julia Google Groups forum provided the solution.

完整的示例应如下所示.

The full example should look like this.

type Status
    Valve1::VectorBool}
    Valve2::Vector{Bool}
    Valve3::Vector{Bool}
    Valve4::Vector{Bool}
    Valve5::Vector{Bool}
    Valve6::Vector{Bool}
    Valve7::Vector{Bool}
    Valve8::Vector{Bool}

    # Constructor for Status type
    function Status(vals::Array{Int64})
        l = int64(length(vals))

        Valve1 = Array(Bool,l)
        Valve2 = Array(Bool,l)
        Valve3 = Array(Bool,l)
        Valve4 = Array(Bool,l)
        Valve5 = Array(Bool,l)
        Valve6 = Array(Bool,l)
        Valve7 = Array(Bool,l)
        Valve8 = Array(Bool,l)

        # Parse Inputs
        for i=1:l
            # Byte 1
            Valve1[i] = vals[i] & 2^(1-1) > 0
            Valve2[i] = vals[i] & 2^(2-1) > 0
            Valve3[i] = vals[i] & 2^(3-1) > 0
            Valve4[i] = vals[i] & 2^(4-1) > 0
            Valve5[i] = vals[i] & 2^(5-1) > 0
            Valve6[i] = vals[i] & 2^(6-1) > 0
            Valve7[i] = vals[i] & 2^(7-1) > 0
            Valve8[i] = vals[i] & 2^(8-1) > 0
        end # End of conversion

        new(Valve1,Valve2,Valve3,Valve4,Valve5,Valve6,Valve7,Valve8)

    end # End of constructor
end # End of type

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