100%分支覆盖率且无故障的测试用例? [英] Test case for 100% branch coverage with no fault?
问题描述
问题陈述是
一种方法具有零错误,您可以编写一个测试套件以覆盖100%的语句覆盖率,但找不到该错误,而另一个测试套件具有100%的分支覆盖率却可以揭示该错误?
这是我为同一方法编写的方法
Here is the method I wrote for the same
public faultyMethod1(int x, int y) {
int X =x;
int Y = y;
if (Y !=0){
Z = X/Y;
} else {
System.out.println("Sorry. That's an DiviDeByZeroException");
}
}
faultyMethod1 (1,2);
faultyMethod1 (2,0);
以上代码实现了具有100%分支覆盖率的测试套件,确实可以揭示故障"
The above code to achieve test suite that has 100% branch coverage that does reveal the fault"
具有100%语句覆盖率但没有发现错误的测试套件怎么样??
What about test suite to that has 100% statement coverage but doesn't find the fault ?
推荐答案
让我们再举一个例子...
Let's make another example...
// The method, according to our imaginary specification, should do:
// return x * y, IF x is less than 2
// return x + y, in any other case
public int doSomething(int x, int y) {
if (x < 2 ) {
return x * x; // this is our bug, it SHOULD be x * y
}
return x + y;
}
现在假设我们有两个测试:
Now imagine we have two tests:
assertEquals(0, doSomething( 0, 12) ); // works, as 0 * 0 == 0 * 12
assertEquals(20, doSomething( 10, 10 ) ); // works fine
因此,现在我们具有100%的测试覆盖率(因为x< 2分支以及另一个分支都已覆盖).但是我们没有发现错误,因为使用零作为x的值会将其隐藏(因为0 *始终为0,所以y是无关紧要的).我们本来需要这样的东西...
So, now we have 100% test coverage (because the x < 2 branch has been covered, as well as the other one). But we didn't find the bug, since using zero as value for x hides it (since 0 * something is always 0, y is irrelevant). We would have needed something like this...
assertEquals(12, doSomething( 1, 12) ); // fails, because it will be 1*1 == 1
对于任何其他情况,包括被零除,都可能发生相同的问题.无法想象一个好的例子,但是我想您已经基本了解了如何获得100%的覆盖率并不意味着找到所有bug的100%. (找到它们的一种很酷的方法是进行突变测试,但这是一个相当高级的主题.)
The same problem can occur for any other situation, including a division by zero. Can't imagine a good example, but I guess you get the basic idea how having a 100% coverage does not mean finding 100% of all bugs. (A cool way to find them would be mutation testing, but that's a pretty advanced topic.)
这篇关于100%分支覆盖率且无故障的测试用例?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!