不能检查，如果对话框显示 [英] Can't check if dialog is showing

问题描述

因此​​，一个对话框打开每次收到一个文本的时间。我希望它不会打开一个，如果有一个已经打开。我试图检查，如果一个是通过使用isShowing（）开放的，但我不断收到方法isShowing（）是undefinded该类型AlertDialog.Builder。这里是坏code的部分。任何帮助将是对，现在这么甜的权利。

 公共类珀普preply延伸活动{
AlertDialog.Builder alertbox;
AlertDialog.Builder警报;
@覆盖
公共无效的onCreate（捆绑savedInstanceState）{
    super.onCreate（savedInstanceState）;
    // prepare警告框
    alertbox.isShowing（）;
    alertbox =新AlertDialog.Builder（本）;
 

解决方案

有是关于 AlertDialog.Builder 类没有isShowing（）方法。有一个关于对话框类，但是。

<一个href=\"http://developer.android.com/reference/android/app/AlertDialog.Builder.html\">AlertDialog.Builder

对话框

这是 AlertDialog.Builder 被用来创建一个 AlertDialog 。一旦你有一个实例 AlertDialog ，就可以判断它是否仍然由然后在其上调用isShowing（）显示。

So a dialog is opened every time a text is received. I want it to not open one if there is one already open. I was trying to check if one was open by using isShowing() but I keep getting the method isShowing() is undefinded for the type AlertDialog.Builder. Here is the section of bad code. Any help would be so sweet right about now.

public class PopUpReply extends Activity{
AlertDialog.Builder alertbox;
AlertDialog.Builder alert;
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    // prepare the alert box
    alertbox.isShowing();
    alertbox = new AlertDialog.Builder(this);

解决方案

There is no isShowing() method on the AlertDialog.Builder class. There is one on the Dialog class though.

AlertDialog.Builder

Dialog

An AlertDialog.Builder is used to create an AlertDialog. Once you have an instance of an AlertDialog, you can determine whether or not it is still showing by then calling isShowing() on it.

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