来自task_struct的完整进程名称 [英] Full process name from task_struct

问题描述

我想从struct task_struct获取完整的进程名称. comm字段仅存储16个字符，而进程名称可以更长.有什么办法可以获取完整的进程名称?
这可以通过从task_struct获取struct vm_area_struct并进一步获取vm_area映射到的文件来完成，但这是不可靠的.

I want to get full process name from struct task_struct. The comm field stores only 16 characters, while process name can be longer. Is there any way to get full process name?
This can be done through by getting struct vm_area_struct from task_struct, and further obtain file to which vm_area is mapped, but this is unreliable.

推荐答案

您是指exe文件名吗?您可以按以下方式获取当前进程的exe:

Did you mean exe file name? You can get the exe of current process as follows :

char *pathname,*p;
mm = current->mm;
if (mm) {
    down_read(&mm->mmap_sem);
    if (mm->exe_file) {
                pathname = kmalloc(PATH_MAX, GFP_ATOMIC);
                if (pathname) {
                      p = d_path(&mm->exe_file->f_path, pathname, PATH_MAX);
                    /*Now you have the path name of exe in p*/
                }
            }
    up_read(&mm->mmap_sem);
}

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