重定向linux模块构建的输出 [英] Redirecting output of linux module build

问题描述

我想重定向模块构建的输出，以将工件与源代码分开.

I'd like to redirect the output of my module build to segregate the artifacts from the source.

我的makefile如下:

My makefile looks like:

    obj-m += hello-1.o

all:
    make ARCH=arm CROSS_COMPILE=arm-eabi- -C /work/TI-Android-ICS-4.0.3_AM37x_3.0.0/kernel M=$(PWD) modules

clean:
    make ARCH=arm CROSS_COMPILE=arm-eabi- -C /work/TI-Android-ICS-4.0.3_AM37x_3.0.0/kernel M=$(PWD) clean

这正常工作，除了模块输出恰好在我的源目录中.我尝试在每行中添加O = {我的输出目录的路径}，但后来却无法通过类似...的方式构建.

This works correctly, except that the module output happens to be in my source directory. I tried adding O={path to my output dirctory} in each line, but then it failed to build with something like...

错误:内核配置无效. 缺少include/generated/autoconf.h或include/config/auto.conf. 运行'make oldconfig&&在内核src上进行准备"以对其进行修复.

ERROR: Kernel configuration is invalid. include/generated/autoconf.h or include/config/auto.conf are missing. Run 'make oldconfig && make prepare' on kernel src to fix it.

警告:符号版本转储 /work/development/linux/driver/blah/Module.symvers 不见了;模块将没有依赖关系和modversions.

WARNING: Symbol version dump /work/development/linux/driver/blah/Module.symvers is missing; modules will have no dependencies and modversions.

我认为这是基于以下事实:模块构建中使用了内核构建中的一些输出文件，并使用"O =更改了输出目录.

I assume this stems from the fact that there is some output file from the kernel build that's used in the module build, and changing the output directory with "O=" collides with that.

是否有一种方法可以使用现有的构建基础架构来完成此任务?

Is there a method for accomplishing this using the existing build infrastructure?

推荐答案

此Makefile将解决您的查询

This Makefile will solve your query

 obj-m += hello-1.o

all:
make ARCH=arm CROSS_COMPILE=arm-eabi- -C /work/TI-Android-ICS-4.0.3_AM37x_3.0.0/kernel M=$(PWD) modules_install INSTALL_MOD_PATH=<output directory for modules>

clean:
make ARCH=arm CROSS_COMPILE=arm-eabi- -C /work/TI-Android-ICS-4.0.3_AM37x_3.0.0/kernel M=$(PWD) clean

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