Python，Kivy，"AssertionError:无人不能调用"通过按钮调用函数时出错 [英] Python, Kivy, "AssertionError: None is not callable" Error on function call by button

问题描述

因此，我希望使用此代码在按下按钮时调用一个函数:

So I whant to use this code to call a function on a button press:

botao_ok.bind(on_press=f_adicionar_socios(txt_n_socio.text,txt_nome.text,txt_filho_de.text,txt_filho_e_de.text,txt_data_nas.text,txt_tipo_ID.text,txt_num_ID.text,txt_NIF.text,txt_morada_rua.text,txt_morada_localidade.text,txt_codigo_postal.text,txt_tel_fixo.text,txt_telemovel.text,txt_email.text,txt_tipo_socio.text,txt_data_admicao.text,txt_zona.text,txt_actividade.text,txt_actividade_de.text,txt_actividade_ate.text,txt_observacoes.text))

但是为了简单起见，我只需要解决这个问题:

But to keep it simple, I only need to solve this problem:

#My Function
def teste_(nome):
    print nome
#Button
botao_ok.bind(on_press=teste_('Ola'))
# Button is inside a Class MYApp

并显示错误消息:AssertionError:None不可调用

and it gives the error: AssertionError: None is not callable

我竭尽全力，无法解决这个问题... 谢谢

Ive tryied everything I tough off and can't solve this... Thank you

推荐答案

编写teste_('Ola')时，该函数运行并返回None

When you write teste_('Ola') the function runs and returns None

所以当你写

botao_ok.bind(on_press=teste_('Ola'))

它实际上设置为:

botao_ok.bind(on_press=None)

简而言之是造成您的问题的原因.

Which in short is causing your problem.

为了使其能够调用teste_('Ola')按下按钮时，您可以使用lambda函数:

In order to get it to call teste_('Ola') When the button is pressed, you could use a lambda function:

botao_ok.bind(on_press=lambda x:teste_('Ola'))

这篇关于Python，Kivy，"AssertionError:无人不能调用"通过按钮调用函数时出错的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！