过滤不在另一个阵列中的阵列 [英] Filter Array Not in Another Array

问题描述

需要根据另一个数组过滤一个数组.敲除功能中是否有util函数?否则我需要使用javascript

Need to filter one array based on another array. Is there a util function in knock out ? else i need to go with javascript

第一:

var obj1 = [{
    "visible": "true",
    "id": 1
}, {
    "visible": "true",
    "id": 2
}, {
    "visible": "true",
    "id": 3
}, {
    "Name": "Test3",
    "id": 4
}];

第二个:

var obj2 = [ 2,3]

现在我需要基于obj2过滤obj1并从obj2中返回不在上述数据中的obj2 omittng 2,3中的项目(与对象1 Id 进行比较)

Now i need to filter obj1 based on obj2 and return items from obj1 that are not in obj2 omittng 2,3 in the above data (Comparison on object 1 Id)

输出:

[{
    "visible": "true",
    "id": 1
}, {
    "Name": "Test3",
    "id": 4
}];

推荐答案

您可以简单地使用filter在obj1中运行，并在obj2上使用indexOf来查看它是否存在.如果值不在数组中，则indexOf返回-1，并且当回调返回true时filter包括该项.

You can simply run through obj1 using filter and use indexOf on obj2 to see if it exists. indexOf returns -1 if the value isn't in the array, and filter includes the item when the callback returns true.

var arr = obj1.filter(function(item){
  return obj2.indexOf(item.id) === -1;
});

---

使用更新的ES语法和API，它变得更加简单:

---

With newer ES syntax and APIs, it becomes simpler:

const arr = obj1.filter(i => obj2.includes(i.id))

这篇关于过滤不在另一个阵列中的阵列的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！