使用正则表达式进行敲除验证以验证电话号码 [英] Knockout-Validation Using Regular Expression to Validate a Phone Number

问题描述

我正在尝试使用Knockout-Validation向我的一个可观察对象添加一个简单的正则表达式验证.

I am trying to add a simple regular expression validation to one of my observables using Knockout-Validation.

我有以下内容:

self.ContactPhone = ko.observable().extend({
            required: true,
            pattern: {
                message: 'Invalid phone number.',
                params: '^\D?(\d{3})\D?\D?(\d{3})\D?(\d{4})$'
            }
        });

但是，无论我输入什么，它都会返回消息无效的电话号码".我需要格式化表达式的某种方式吗?我已经使用纯JavaScript测试了它，并且效果很好.

However, no matter what I enter, it returns the message 'Invalid phone number.' Is there a certain way I need to format the expression? I've tested it using purely JavaScript and it works fine.

推荐答案

您需要转义反斜杠，否则javascript会将您的一个反斜杠本身视为下一个字符的转义字符.这是因为这是一个字符串，而不是正则表达式文字.

You need to escape your backslashes otherwise javascript treats your one backslash itself as an escape-character for the next character. This is because this is a string and not a regexp literal.

实际上，我刚刚检查了一下，您可以只使用一个正则表达式文字，所以这些都可以做到:

Actually I just checked, and you can just use a regexp literal instead, so either of these would do it:

http://jsfiddle.net/antishok/ED3Mh/2/

self.ContactPhone = ko.observable().extend({
    required: true,
    pattern: {
        message: 'Invalid phone number.',
        params: /^\D?(\d{3})\D?\D?(\d{3})\D?(\d{4})$/            
    }
});

或:

params: '^\\D?(\\d{3})\\D?\\D?(\\d{3})\\D?(\\d{4})$'

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