将一个函数中变量的值传递给同一类中的另一个函数 [英] To pass value of a variable in one function to another function in same class

问题描述

我有一个类Block_Model(实际上是Kohana框架中的一个模型)，带有2个方法input()和output().

I have a class Block_Model (actually a model in Kohana framework) with 2 methods input()and output().

class Block_Model extends ORM {
    function input($arg) {
        //...
    }
    function output() {
        //...
    }
    //...
}

方法input是从称为Home_Controller的控制器内部编写的函数调用的，并将参数传递给方法input.

The method input is called from a function written inside a controller called Home_Controller and it passes an argument to the method input.

class Home_Controller extends Controller {
    function doSomething() {
        $block = new Block_Model();
        //...
        $block->input($val);
        //...
    }
}

如何在方法output()中访问传递给input()的参数?

How can I make the argument passed to input() be accessible in the method output()?

推荐答案

这类似于@silent的答案，但是您可以结合使用setter&一种方法中的吸气剂.

This is similar to @silent's answer, but you can combine setter & getter in one method.

protected $_foo;

public function foo($val = NULL)
{
    if ($val === NULL)
    {
        // its a getter!
        return $this->_foo;
    }

    // its a setter 
    $this->_foo = $val;
    // return current object, so it becomes a chainable method
    return $this;
}

现在您可以使用$value = $object->foo();和$object->foo($value)->do_something_else();

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