无法创建类的实例-ViewModel [英] Cannot create an instance of class - ViewModel

问题描述

我正在跟踪google的示例，该示例在Java中，但是当我在kotlin中重写它时，无法实例化该类. 我正在学习视图模型.我是否怀疑我的 kotlin 代码的语法是否正确.

I'm following an example of google, the example is in java but when I rewrite it in kotlin I can not instantiate the class. I am learning viewmodel. I have a lot of doubt if I messed up the syntax of my kotlin code.

https://github.com/googlecodelabs/android-room-with -a-视图

类MainActivity:AppCompatActivity(){

class MainActivity: AppCompatActivity() {

//    private lateinit var mWordViewModel: WordViewModel //not works
    private var mWordViewModel: WordViewModel? = null //not works
    private var wordListAdapter: WordListAdapter?= null

    override fun onCreate(savedInstanceState: Bundle?) {
        super.onCreate(savedInstanceState)
        setContentView(R.layout.activity_main)
        setSupportActionBar(toolbar)

        try {
            mWordViewModel = ViewModelProviders.of(this@MainActivity).get(WordViewModel::class.java)
        }catch (e: Exception){
            e.printStackTrace()
        }

...

class WordViewModel(application: Application): AndroidViewModel(application) {

//    super(application)

    private var mRepository: WordRepository? = null
    private var mAllWords: LiveData<List<Word>>? = null

    init {
        mRepository = WordRepository(application)
        mAllWords = mRepository?.getAllWords()
    }

...

class WordRepository(application: Application) {

    private var mWordDao: WordDao? = null
    private var mAllWords: LiveData<List<Word>>? = null

    init {
        val db = WordRoomDatabase.getDatabase(application)
        mWordDao = db.wordDao()
        mAllWords = mWordDao!!.getAlphabetizeWords()
    }

...

@Database(entities = arrayOf(Word::class), version = 1)
abstract class WordRoomDatabase: RoomDatabase(){

    abstract fun wordDao(): WordDao

    companion object {
        @JvmStatic
        private var INSTANCE: WordRoomDatabase? = null

        fun getDatabase(context: Context): WordRoomDatabase {
            if (INSTANCE == null) {
                synchronized(WordRoomDatabase::class.java) {
                    if (INSTANCE == null) {
                        INSTANCE = Room.databaseBuilder(context.applicationContext, WordRoomDatabase::class.java, "word_database")
                                .fallbackToDestructiveMigration()
                                .addCallback(sRoomDatabaseCallback)
                                .build()
                    }
                }
            }
            return INSTANCE!!
        }

推荐答案

@zunjae

错误

1-语法代码koltin.

1 - Syntax code koltin.

2-项目配置.

class MainActivity: AppCompatActivity() {
mWordViewModel = ViewModelProviders.of(this@MainActivity).get(WordViewModel(application)::class.java)

...

class WordViewModel constructor (application: Application):  AndroidViewModel(application){

...

class WordRepository constructor(application: Application) {

...

添加应用程序build.gradle

add app build.gradle

apply plugin: 'kotlin-kapt'

kapt "android.arch.lifecycle:extensions:$rootProject.archLifecycleVersion"
kapt "android.arch.persistence.room:compiler:$rootProject.roomVersion"

这篇关于无法创建类的实例-ViewModel的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！