Kotlin:Lambda，范围，地图，过滤器和缩小/折叠 [英] Kotlin: Lambdas, range, map, filter and reduce/fold

问题描述

使用lambda，范围，地图，过滤和缩小/折叠等功能，计算1到1000之间的数字之和，这些数字可被5或3整除并打印结果.

Using the functions such as lambdas, range, map, filter and reduce/fold, calculate the sum of numbers between 1 and 1000 which are divisible by 5 or 3 and print the result.

推荐答案

我们可以执行以下操作:

We can do the following:

println((1..1000).filter{ it % 3 == 0 || it % 5 == 0 }.reduce{sum, element -> sum + element})

我们也可以使用如下所示的sum来代替reduce:

Instead of reduce we could use sum as well which would look like this:

println((1..1000).filter{ it % 3 == 0 || it % 5 == 0 }.sum())

这篇关于Kotlin:Lambda，范围，地图，过滤器和缩小/折叠的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！