KSH检查字符串是否以子字符串开头 [英] KSH check if string starts with substring
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问题描述
我需要检查变量是否具有以指定子字符串开头的字符串值.
I need to check if the variable has value of string which starts with specified substring.
在Python中,将是这样的:
In Python it would be something like this:
foo = 'abcdef'
if foo.startswith('abc'):
print 'Success'
在Ksh中检查strig $foo
是否以子字符串bar
开头的最明确的方法是什么?
What is the most explicit way to check in Ksh whether strig $foo
starts with substring bar
?
推荐答案
这很简单,但看起来有点奇怪:
It's very simple but looks a bit odd:
if [[ "$foo" == abc* ]]; then ...
人们会假设ksh会使用当前目录中的文件扩展模式,但是相反,它会进行模式匹配.但是,您需要[[
.单个[
将不起作用.如果foo
中没有空格,则引号不是必须的.
One would assume that ksh would expand the pattern with the files in the current directory but instead, it does pattern matching. You need the [[
, though. Single [
won't work. The quotes are not strictly necessary if there are no blanks in foo
.
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