将awk的结果放入数组 [英] Put result of awk into an array

问题描述

当我在终端上运行以下命令时，

awk /984/ $files | awk -F, '{OFS=",";print $1,$4,$17}'

哪里

files=`ls`

我得到以下输出:

2013/08/18 12:51:37,11,724
2013/08/18 12:48:02,227,84769

我希望创建一个脚本，运行该命令并将上述结果分配给数组:(将单独的行作为单独的元素)

I wish to create a script, run that command and assign the above result to an array in this way: (Separate lines as separate elements)

array[0] = 2013/08/18 12:51:37,11,724
array[1] = 2013/08/18 12:48:02,227,84769

但是

都不是

result=($(awk /string/ $files | awk -F, '{OFS=",";print $1,$4,$17}'))

也不，

result2=`awk /string/ $files | awk -F, '{OFS=",";print $1,$4,$17}'`

实现了我的目的.

如何获取我指定的数组?

How to get an array like I specified?

推荐答案

当您说:

result=($(awk /string/ $files | awk -F, '{OFS=",";print $1,$4,$17}'))

输出将被空格分隔.将IFS设置为换行符，您将看到所需的结果.说:

the output would be split by whitespace. Set IFS to a newline character, and you should see the desired result. Say:

IFS=$'\n' result=($(awk /string/ $files | awk -F, '{OFS=",";print $1,$4,$17}'))

代替将不同的行输出捕获到数组中.

instead to capture different lines of output into an array.

这篇关于将awk的结果放入数组的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！