在shell脚本中将输出抑制到屏幕 [英] suppress the output to screen in shell script

问题描述

嗨 我写了一个小脚本:

Hi i have written a small script:

#!/usr/bin/ksh

for i in *.DAT
do
awk 'BEGIN{OFS=FS=","}$3~/^353/{$3="353861958962"}{print}' $i >> $i_changed
awk '$3~/^353/' $i_changed >> $i_353
rm -rf $i_changed
done

exit

我对其进行了测试，并对其进行了很好的测试. 但这是将输出提供给屏幕，我不需要将输出提供给屏幕. 我只需要制成$i_353

i tested it and its wrking fine. But it is giving the output to screen i dont need the output to screen. i simply need the final file that is made $i_353

怎么可能?

推荐答案

用大括号括住脚本正文，然后重定向到/dev/null:

Wrap the body of the script in braces and redirect to /dev/null:

#!/usr/bin/ksh

{
for i in *.DAT
do
    awk 'BEGIN{OFS=FS=","}$3~/^353/{$3="353861958962"}{print}' $i >> $i_changed
    awk '$3~/^353/' $i_changed >> $i_353
    rm -rf $i_changed
done
} >/dev/null 2>&1

这也将错误发送到位桶.那可能不是一个好主意.如果您不想这样做，请删除2>&1重定向.

This sends errors to the bit-bucket too. That may not be such a good idea; if you don't want that, remove the 2>&1 redirection.

也:当心-您可能需要使用${i}_changed和${i}_353.这就是为什么输出不会发送到文件的原因...您的变量${i_changed}和${i_353}未初始化，因此重定向未命名文件.

Also: beware - you probably need to use ${i}_changed and ${i}_353. This is why the output is not going to the files...your variables ${i_changed} and ${i_353} are not initialized, and hence the redirections don't name a file.

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