退出Ksh While循环的惯用方式 [英] Idiomatic way to exit ksh while loop

问题描述

我有以下5秒钟的计时器，它每秒钟打印一个星号.

I've the following 5 second timer which prints an asterisk for each second.

timer () {
  i=1
  trap 'i=5' INT

  while [[ $i -le 5 ]]; do
    sleep 1
    printf "*"
    ((i+=1))
  done
}

不知何故，陷阱块似乎有点怪异，我想知道是否有更正确的方法来中断整个循环(而不仅仅是当前的睡眠周期).我尝试过:

Somehow the trap chunk seems a little hackish and I wonder if there's a more correct way to interrupt the entire loop (not just the current sleep cycle). I've tried:

trap 'print "foo"' INT

函数内部和外部的不同位置，但是正如我之前提到的那样，这只是中断了当前的睡眠周期.

at various locations inside and outside the function, but as I alluded to before, that just interrupts the current sleep cycle.

推荐答案

在bash中对我有用:

This works for me in bash:

#!/bin/bash

function timer {

    trap "break" INT

    i=0
    while (( ++i <= 5 )); do
        sleep 1
        printf '*'
    done
}

echo "Starting timer"
timer

echo "Exited timer"
echo "Doing other stuff...."

，这在ksh中(请注意trap语句的不同位置):

and this in ksh (note the different location of the trap statement):

#!/bin/ksh

function timer {

    trap "break" INT

    i=0
    while (( ++i <= 5 )); do
        sleep 1
        printf '*'
    done
}

echo "Starting timer"
timer

echo "Exited timer"
echo "Doing other stuff...."

这篇关于退出Ksh While循环的惯用方式的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！