排序月份(带字符串)算法 [英] Sort months ( with strings ) algorithm

问题描述

我有这个月份的数组:

["January", "March", "December" , "October" ]

我想像这样排序:

["January", "March", "October", "December" ] 

我目前正在以"if/else"可怕的级联方式思考，但是我想知道是否还有其他方法可以做到这一点.

I'm currently thinking in a "if/else" horrible cascade but I wonder if there is some other way to do this.

糟糕的是，我只需要使用"string"(即，不使用Date对象或类似的东西)

The bad part is that I need to do this only with "string" ( that is, without using Date object or anything like that )

什么是好的方法?

推荐答案

如果我可以提供自定义排序顺序，则可以创建一个定义正确顺序的列表:

If I had a way to supply a custom sorting order, I'd create a list defining the correct order:

correct = List("January", "February", "March", ...)

然后按该列表中的位置进行排序，例如:

And then sort by the position in that list, something like:

toSort.sort(a, b) => compare(correct.index(a), correct.index(b))

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